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goldenfox [79]
3 years ago
9

How would i graph y=2x+5

Mathematics
1 answer:
Anna35 [415]3 years ago
6 0

To be able to graph this you need to start on -2 on the y-axis then move up 5 then 1 to the right

The dot should be on (1,3)

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Can someone please help me on this one!!!!
VashaNatasha [74]
This appears to be about rules of exponents as much as anything. The applicable "definitions, identities, and properties" are
  i^0 = 1 . . . . . as is true for any non-zero value to the zero power
  i^1 = i . . . . . . as is true for any value to the first power
  i^2 = -1 . . . . . from the definition of i
  i^3 = -i . . . . . = (i^2)·(i^1) = -1·i = -i
  i^n = i^(n mod 4) . . . . . where "n mod 4" is the remainder after division by 4


1. = -3^4·i^(3·2+0+2·4) = -81·i^14 = 81

2. = i^((3-5)·2+0 = i^-4 = 1

3. = -2^2·i^(4+2+2+(-1+1+5)·3+0) = -4·i^23 = 4i

4. = i^(3+(2+3+4+0+2+5)·2) = i^35 = -i

5 0
3 years ago
Find the value of y picture *****
77julia77 [94]
I think its 54 too soo
3 0
3 years ago
Mrs.Bailey had 15 pieces of candy. She gave away some candy and has 3 pieces left. What is the percent decrease of candy?
Alenkasestr [34]

Answer:

12

Step-by-step explanation:

subtract 15 away from 3 and you have 12 so that how Mrs. Bailey has 3 pieces of candy left

3 0
3 years ago
Read 2 more answers
Select all of the choices that are equal to (-5) - (-12)<br><br> -7<br> 7<br> (-5)+12<br> (-5)+(-12)
Roman55 [17]

Answer:

the awnser is. (-5) + (-12)

7 0
3 years ago
Read 2 more answers
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
3 years ago
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