At Venn diagram there are 4 parts (20 pieces):
1. Colored only in blue - quadrilaterals with four equal side lengths (3 pieces);
2. Colored only in orange - quadrilaterals with four right angles (6 pieces);
3. Colored in both blue and orange - quadrilaterals with four right angles and with four equal side lengths (2 pieces);
4. Colored in white - quadrilaterals withoutprevious two properties (9 pieces).
Consider events:
A - a randomly chosen quadrilateral has four right angles;
B - a randomly chosen quadrilateral has four equal side lengths;
Use formula
to find the probability that a randomly selected quadrilateral with 4 right angles also has four equal side lengths:

Answer: Pr=0.25
Answer:
Step-by-step explanation:
Answer: x<16
Step-by-step explanation: Mason subtracted 5 from 11 and got 6, when he really should have added 5 to 11 to get x<16.
Answer:
Solution given:
m∠ADB=(4x−12)°
m∠CDB=(3x+6)°
m∠ADC =?
Since diagonal BD bisect the angle <ADC
so
m∠ADB= m∠ADC
(4x-12)°=(3x+6)°
4x-3x=6-12
x=12+6
x=18°
again.
<ADB=m∠ADB+ m∠ADC=4×18-12+3×18+6=120°
So
<u>the m∠</u><u>ADC</u><u> </u><u>=</u><u>1</u><u>2</u><u>0</u><u>°</u>
Answer:
9:15
Step-by-step explanation:
