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nika2105 [10]
3 years ago
8

Please help me on this will give you brainliest

Mathematics
2 answers:
beks73 [17]3 years ago
7 0
Aren’t you supposed to multiply the exponents to where it’s 5^24 ?
kenny6666 [7]3 years ago
7 0

24

(5)

Explain your answer:

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40% of oatypop cereal boxes contain a prize Hannah plans to keep buying cereal until she gets a prize what is the probability Ha
stepan [7]

Answer:

D.

Step-by-step explanation:

took the test

7 0
2 years ago
PLEASE HELP ILL DO ANYTHING PLEASE. ill give brainliest
Amanda [17]

Answer:

If the ball cost 10 cents and the bat costs $1.00 more than the ball, then the bat would cost $1.10 for a grand total of $1.20. The correct answer to this problem is that the ball costs 5 cents and the bat costs — at a dollar more — $1.05 for a grand total of $1.10.

'Now give me brainiest

8 0
3 years ago
Read 2 more answers
What is the value of x?<br> Enter your answer in the box
klasskru [66]

Answer:

x is the number you have to multiply by the given number to get the whole value

Step-by-step explanation:

5x*7 x=35

6 0
4 years ago
Find the M&lt;6 if m&lt;2 = 75
ryzh [129]

Answer:

75

Step-by-step explanation:

angle 2 and angle 6 are corresponding angles, because the lines are parallel and cut by a transversal, corresponding angles are congruent, thus if angle 2 is 75 degrees then angle 6 is 75 degrees

8 0
3 years ago
The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt
Marizza181 [45]

Answer:

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

L=w+2

now, we can find area

A=L\times W

now, we can plug it

A=(w+2)\times w

A=w^2+2w

we are given area =6

so, we can set it equal

and then we can solve for w

w^2+2w=6

w^2+2w-6=0

we can use quadratic formula

ax^2+bx+c=0

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}

w=-1+\sqrt{7},\:w=-1-\sqrt{7}

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

7 0
3 years ago
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