Answer: T.S.A = 4512cm^2
volume = 18900cm^3
weight = 17.01 kg
Step-by-step explanation:
T.S.A of cuboid = 2(lb+bh+lh)
= 2(42x25 + 25x18 + 42x18)
=2(1050 + 450 + 756)
=2 x 2256
= 4512cm^2
to find weight, we've to find the volume of the ice cube
therefore, volume of a cuboid = lbh
=42 x 25 x 28
=18900cm^3
weight of 1cm^3 of ice = 0.9grams
therefore weight of 18900cm^3 of ice = 18900 x 0.9
= 17010 grams = 17.01kg
Hope it helped u,
pls mark as the brainliest - Ayaan707 for help :) -
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Subtract 4 from both sides of the equation. It looks familiar now right? (y=mx+b is a linear equation)
Answer:
C. -5/7
Step-by-step explanation:
Take your y values and subtract them (2- -3) = 5
Then do the same with your x values in the same order (-4 -3) = -7
2 / (z-5) = z / (0.5z^2 + 7)
cross multiply
z(z - 5) = 2(0.5z^2 + 7) =
z^2 - 5z = z^2 + 14 =
z^2 - z^2 - 5z = 14
-5z = 14
z = -14/5
