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borishaifa [10]
4 years ago
10

How do I simplify this (sinx)/(secx+1)

Mathematics
1 answer:
pochemuha4 years ago
6 0

Answer:

Step-by-step explanation:

\frac{sin~x}{sec~x+1} =\frac{sin~x}{\frac{1}{cos~x}+1  } =\frac{sin~x~cos~x}{1+cos~x} \\=\frac{sin~x~cos~x}{1+cos~x} \times \frac{1-cos~x}{1-cos~x} \\=\frac{sin~x~cos~x(1-cos~x)}{1-cos^2 x} \\=\frac{sin~x~cos~x(1-cos~x)}{sin^2x} \\=\frac{cos~x(1-cos~x)}{sin~x} \\=cos ~x(csc~x-cot~x)\\or\\=cot~x(1-cos~x)

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This is further explained below.

<h3>What is logarithmic function g(x)?</h3>

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In conclusion, the Exponential equation x = ay is defined as analogous to the logarithmic function y = logan. Only when (x = ay), (a > 0), and (a 1) does (y = logan). It is referred to as the logarithmic function of base a. Think about what it implies when the exponential function is inverted: x = ay.

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