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marishachu [46]
3 years ago
14

If line WP is a median and an angle bisector, AP = 3y+11, PH = 7y - 5, angle HWP = x +12, angle PAW = 3x - 2, and angle HWA = 4x

- 16, find x and y. Is WP also an altitude? Explain.
Mathematics
1 answer:
zmey [24]3 years ago
8 0
∠ HWA / 2 = ∠HWP
( 4 x - 16 ) / 2 = x + 12
4 x - 16 = 2 x + 24
2 x = 40
x = 20
AP = PH
3 y + 11 = 7 y - 5
16 = 4 y 
y = 4
∠PAW = 60 - 2 = 58°
∠PWA = 32°, ∠PWH = 32°
∠AWH = 64°
∠WHA = 58°
     Therefore Δ AWH is isosceles. Line WP is an altitude because it bisects the base of an isosceles triangle.



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The minimum value for g(x)=x² - 10x + 16 is -9

<h3>How to determine the minimum value?</h3>

The function is given as:

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