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GaryK [48]
3 years ago
13

Solve the system by substitution. *

Mathematics
1 answer:
baherus [9]3 years ago
6 0

Answer:

(-3,-1)

Step-by-step explanation:

Given equations are :

3x - 2y=-7\ ....(1)\\\\y=-7x - 22...(2)

Put the value of y from equation (2) to equation (1), so,

3x - 2(-7x - 22)=-7\\\\3x+14x+44=-7        

Taking variables on one side and constant on another side.    

17x=-7-44\\\\17x=-51\\\\x=-3

Put x = -3 in equation (2) i.e.

y=-7(-3) - 22\\\\y=-1

So, the value of x and y are (-3) and (-1) respectively.

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Read 2 more answers
Michael’s weight can be represented by the expression 72x^5. Al’s weight can be represented by the expression 9x^7.
podryga [215]

Answer:

a) \frac{72x^5}{9x^7}

b) =\frac{8}{x^2}

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Step-by-step explanation:

Michael's Weight: 72x^5

Al's weight: 9x^7

a) Ratio of Michael's weight to Al's weight: \frac{72x^5}{9x^7}

b) This ratio simplifies to:  \frac{8\times 9x^5}{9x^5\timesx^2}

                                         =\frac{8}{x^2}

c) Yes, If the exponent in each expression were negative, then we have:

Ratio of Michael's weight to Al's weight: \frac{72x^{-5}}{9x^{-7}}

This ratio simplifies to:  8x^{-5--7}=8x^2

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