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Hitman42 [59]
4 years ago
8

40 POINTS!!!!!!!!!!!!! A student observes that the motion of a weight oscillating up and down on a spring can be modeled by the

following equation, where h is the weight's height above the ground, in meters, and t is the time, in seconds. On the graph, plot the points where height, h(t), is at a maximum. h(t)=0.5 x sin(πt+π/2)+1. ANSWERS ARE 2.0 1.0 OR 0.5
Mathematics
1 answer:
Makovka662 [10]4 years ago
5 0

Answer:

ok

Step-by-step explanation:

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zimovet [89]
More students would bike to school because it says "5 more" students bike to school
4 0
3 years ago
Use the order pairs to write a function rule. Give the tule in slope-intercept form.
topjm [15]

to get the equation of any straight line, we simply need two points off of it, so hmmm let's use say (-1 , -1.25) and (8 , -3.5)

(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1.25})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-3.5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3.5}-\stackrel{y1}{(-1.25)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{(-1)}}}\implies \cfrac{-3.5+1.25}{8+1}\implies \cfrac{-2.25}{9}\implies -\cfrac{~~ \frac{225}{100}~~}{\frac{9}{1}} \\\\\\ -\cfrac{225}{100}\cdot \cfrac{1}{9}\implies -\cfrac{9}{4}\cdot \cfrac{1}{9}\implies -\cfrac{1}{4}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1.25)}=\stackrel{m}{-\cfrac{1}{4}}(x-\stackrel{x_1}{(-1)}) \\\\\\ y+1.25=-\cfrac{1}{4}(x+1)\implies y+\cfrac{5}{4}=-\cfrac{1}{4}x-\cfrac{1}{4} \\\\\\ y=-\cfrac{1}{4}x-\cfrac{1}{4}-\cfrac{5}{4}\implies y=-\cfrac{1}{4}x-\cfrac{6}{4}\implies y=-\cfrac{1}{4}x-\cfrac{3}{2}

3 0
2 years ago
What is the value of x?<br> O 2<br> 03<br> 06<br> 07<br> "Е
Svet_ta [14]
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6 0
2 years ago
Help please And how would you get the answer need asap
Rashid [163]
No the 2 equations are not equal
the -1/10, -1/10 can't be subtracted from 1 3/10g
they are not like terms
the proper equation is
1/5g converts to 2/10g
2/10g - 1g + 1 3/10 g = 5/10g or 1/2g
1/2g - 2/10 is final equation
4 0
3 years ago
Hector, Sam, Ted, and Gina are comparing their savings. Hector saved twice as much money as Sam. Ted saved $100 more than Hector
lutik1710 [3]

Answer:

2x+50

Step-by-step explanation:

Given: Hector saved twice as much money as Sam.

           Ted saved $100 more than Hector.

           Gina saved $50 less than Ted.

As given, lets assume the amount of money Sam has in saving be "x".

Now, finding saving of each person given.

Writing the algebric expression of each´s saving amount.

we know, Hector saved twice as much money as Sam.

∴ Hector saving= \$2x

Also, Ted saved $100 more than Hector.

∴ Ted´s saving= \$(2x+100)

Next finding Gina´s saving

As given, Gina saved $50 less than Ted.

∴ Gina´s saving= \$ (2x+100)-\$ 50

Opening parenthesis and solving it.

⇒ Gina´s saving= \$ 2x+\$50

Algebric expression of Gina´s saving= 2x+50

5 0
3 years ago
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