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3 years ago

Write equations and solve for x and y don't know what to do pls help

Mathematics

1 answer:

irina1246 [14]3 years ago

8 0

X=9
y= 24
Hope it helps!
#MissionExam001

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Help me please I don’t know it

avanturin [10]

C both of these is correct

4 0

2 years ago

Find the distance between the points ( – 9, – 4) and ( – 4,8).

Dmitriy789 [7]

Answer:

$Distance=13\ units$

Step-by-step explanation:

Distance between two points: Distance between two pints $(x_1,y_1)\ and\ (x_2,y_2)$ is given by

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between $(-9,-4)\ and\ (-4,8).$

$d=\sqrt{(-4-(-9))^2+(8-(-4))^2}\\\\d=\sqrt{(-4+9)^2+(8+4)^2}\\\\d=\sqrt{(5)^2+(12)^2}=\sqrt{25+144}\\\\d=\sqrt{169}\\\\d=13$

6 0

2 years ago

How do u do this ? I'm so confused I really need help

Art [367]

Well what do u need help with can u explain?

5 0

3 years ago

10. JKLM is a rhombus KLN is a triangle. Find MKN.

rjkz [21]

Answer:

65°

Step-by-step explanation:

JM = JK (all sides of a rhombus are equal)

Angle JKM = 25° (isosceles triangle)

Angle JKL = 50° (consecutive angles of rhombus)

Angle MKL = 25° (angle subtraction)

Angle MLK = 130° (opposite angles of a rhombus)

Angle KLN = 50° (angles on a straight line)

Angle LKN = 40° (angle sum of triangle)

Angle MKN = 65° (angle addition)

7 0

1 year ago

A jet is coming in for a landing. It's currently 25,000 feet in

Mariana [72]

The angle of depression is 29.0521°. So it is a safe landing.

Step-by-step explanation:

Step 1:

The plane is flying at a height of 25,000 feet and 45,000 feet away from the landing strip. Assume it lands with an angle of depression of x°.

So a right-angled triangle can be formed using these measurements. The triangle's opposite side measures 25,000 feet while the adjacent side measures 45,000 feet. The angle of the triangle is x°.

To determine the value of x, we calculate the tan of the given triangle.

$tanx = \frac{opposite side}{adjacent side}.$

Step 2:

The length of the opposite side = 25,000 feet.

The length of the adjacent side = 45,000 feet.

$tan x = \frac{25,000}{45,000} = 0.5555.$

So x = 29.0521°. Since x < 30°, it is a safe landing.

8 0

3 years ago