Hope this picture helps!
<span>The 2.7 has been broken into 2 and 0.7, and then both of these parts have been multiplied by 3, giving you the two answers of 6 and 2.1 shown. Adding these two together gives you the answer of 8.1. </span>
Answer:
joint variation means L (safe load) is directly proportional to both w and d2
inverse proportionality means L = k/l
So the equation is:
L = k(wd2/l)
You are given:
w = 6 in
d = 5 in
l = 12 ft
L = 7666 lbs
7666 = k(6*52/12)
Solve for the constant, k.
7666 = k (6*25/12)
7666 = k (150/12)
7666 = k (12.5)
613.28 lbs/(ft.in3) = k
Use this k-value to solve for L in the last part of the question.
What safe load, L would a beam 3 in. wide, 7 in. deep and 15 ft long of the same material support? (Round off your answer to the nearest pound.)
w = 3 in
d =7 in
l = 15 ft
k = 613.28 lbs/(ft.in3)
Final Safe load = 6010.144 lbs *** Edited for clarity and to fix a multiplication erro
Answer: 5/12
Step-by-step explanation:
The word "Mathematical" has 12 letters, and 5 of them are vowels.
Answer:
d. 9x + 63 and 63 square feet
Step-by-step explanation:
Given
Original
Extended
Required
Determine an expression and the value of the extended area
First, we calculate the area of the original desk
From the given parameters, we have:
--- area of the new surface
Open bracket
The area of the new surface is the summation of the area of the original desk and the area of the extended portion (E)
So:
Make E the subject
Hence, the area of the extended portion is 63