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ss7ja [257]
3 years ago
11

6.018×9 find de estimates

Mathematics
1 answer:
Step2247 [10]3 years ago
5 0
You need to round 6.018 to 6 then multiply it by 9 which results in 54!
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Can someone explain major and minor arcs in relation to circles.
Lelechka [254]
A Major Arc within a circle is something that that is more than half of the circle, and therefore, larger than the minor arc. The way in which this could be used in an example is; Tony has a pizza with 8 slices, 6 of these slices are pepperoni and 2 are chilli beef. In this case, the pepperoni slices are the major arc and the chilli beef slices are the minor arc.
The Major Arc will always be bigger than the minor arc- whether this is 181 degrees to 179, or whether this is 350 degrees to 10 degrees.
The Minor Arc is always the smallest arc, and this can be explained by; Benedict has an apple pie that has 10 slices, between him and his friends, they have eaten four slices. In this case, they have eaten the 'minor arc'
There is a picture attached, and this is the examples of a major and a minor arc.
Hope this has been able to help you :) 

3 0
3 years ago
A theater wants to build movable steps that they can use to go on and off the stage. They want the steps to have enough space in
earnstyle [38]

Answer:

0.045

Step-by-step explanation:

khan

8 0
3 years ago
Please assist me with this problem​
iren [92.7K]

Answer:

b. x + 1

Step-by-step explanation:

x¹⁶ − x¹⁴ = k (x¹⁵ − x¹⁴)

x¹⁴ (x² − 1) = k x¹⁴ (x − 1)

x² − 1 = k (x − 1)

(x − 1) (x + 1) = k (x − 1)

x + 1 = k

4 0
3 years ago
An animal park has lions,tiger an zebras.2/5 of the animals are lions and 3/10 of the animals are zebras. what percentage are ti
maksim [4K]

Answer:

3/10

Step-by-step explanation:

You have to make them the same fraction.

2/5 = 4/10

3/10 =3/10

3/10 + 4/10 = 7/10

10/10 - 10/10 =3/10

3/10 is the amount of tigers.

4 0
2 years ago
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
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