1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
brilliants [131]
3 years ago
7

What’s the answer to this?

Mathematics
1 answer:
babymother [125]3 years ago
8 0

Answer:

○ \displaystyle x > -3 \\ 5y ≥ -4x - 10

Step-by-step explanation:

This system of inequalities has a shared portion at the origin, so we can easily jump to using the zero-interval test [test point (0, 0)] to verify the inequalities as false or true:

\displaystyle 5[0] ≥ -4[0] - 10 → 0 ≥ -10☑

\displaystyle 0 > -3☑

Plus, the top inequality has a <em>dashed </em><em>line</em><em> </em>["<" or ">"], and the bottom inequality has a solid line, so this must have an equivalence line underneath each inequality symbol ["≤" or "≥"].

** Hold on though! Although it looks obvious about what the second inequality is, we need to double-check and make sure anyway, just to be on the safe side ☺:

\displaystyle \frac{5y}{5} ≥ \frac{-4x - 10}{5} → y ≥ -\frac{4}{5}x - 2

From the y-intercept of \displaystyle [0, -2],we do \displaystyle \frac{rise}{run}by either moving four blocks <em>north</em><em> </em>over five blocks <em>west</em><em> </em>or four blocks <em>south</em><em> </em>over five blocks <em>east</em><em> </em>[<em>west</em> and <em>south</em> are negatives]. This IS what our solid graph looks like, so we are correct!

So, from all what was explained, you have your answer.

I am joyous to assist you anytime.

You might be interested in
This is the table i need help with
Papessa [141]
2.3 is the other length
Hope this helps :)
8 0
3 years ago
Read 2 more answers
Kite EFGH is inscribed in a rectangle where F and H are midpoints of parallel sides. The area of EFGH is 35 square units. What i
sasho [114]

*see attachment for the figure described

Answer:

5 units

Step-by-step explanation:

==>Given the figure attached below, let where FH and EG intercepted be K.

Since FH are midpoints of parallel lines, KE = KG = x.

Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.

Area of kite = ½ × d1 × d2

Where d1 = KH = 7

d2 = EG = KE + KG = x + x = 2x

Area of kite EFGH = 35

THUS:

35 = ½ × 7 × 2x

35 = 1 × 7 × x

35 = 7x

Divide both sides by 7

35/7 = x

x = 5

4 0
3 years ago
How do you solve number 13 and 14?
Ulleksa [173]
This is what I got hope u get it right gl

3 0
3 years ago
Which angles are alternate exterior angles with angle 11?
Elena-2011 [213]

The above questions answer is 8 and 14

8 0
3 years ago
In this equation you have to solve for x​
lidiya [134]

Answer:

Step-by-step explanation:

tan 36° = x/40

x = 40 * tan 36°

x ≈ 29.1

6 0
2 years ago
Other questions:
  • Given: ABCD trapezoid BC=1.2m, AD=1.8m AB=1.5m, CD=1.2m AB ∩ CD =K Find: BK and CK
    10·1 answer
  • Read the following sentences from "The Third Bank of the River."
    7·1 answer
  • Here is the question<br> |<br> |<br> |<br> |<br> v
    10·1 answer
  • What is a factor can you ples tell me what a factor is
    11·1 answer
  • A triangle with an area of 2/3 cm² is dilated by a factor of 6.
    15·2 answers
  • Jay is trying to calculate his grade for his math class. If his test scores are 87, 80, 96, 94, and 88, what is his average grad
    5·1 answer
  • Factor the greatest common factor. 5xy4-20x2y3
    9·1 answer
  • Antisocial personality disorder (ASPD) is characterized by deceitfulness, reckless disregard for the well-being of others, a dim
    13·1 answer
  • How to factor <br> 49y^{2}-9x^{2}
    14·1 answer
  • A group of friends were working on a student film that had a budget of $600. They used $198 of their budget on props. What perce
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!