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boyakko [2]
3 years ago
15

If you work for an hourly wage, your gross pay is a function of the number of hours that you work. Your hourly wage is $8.50 per

hour. Let n represent the number of hours worked and f(n) represent the gross pay. Write an equation for f(n) in terms of n.
Mathematics
1 answer:
Ket [755]3 years ago
3 0

Answer:

f(n) = 8.5n

Step-by-step explanation:

$8.50 * n = Gross

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Pls help!
Amiraneli [1.4K]

Answer:

78

Step-by-step explanation:

you multiply

7 0
3 years ago
Read 2 more answers
Which expression is a factor of 21x2 + 13x – 20?A. 3x – 4B. 7x - 5C. 7x + 4D. 3x + 5
LUCKY_DIMON [66]

Answer:

B. 7x - 5

Explanation

Given the expression 21x^2 + 13x – 20, to get which of the given expression is a factor we will have to factorize the equation first as shown;

21x^2 + 13x – 20

= 21x^2 + 28x - 15x - 20

= 7x(3x+4) -5(3x+4)

= (7x-5)(3x+4)

Hence one of the factors is 7x - 5

8 0
1 year ago
If you received an annual salary of 33500 paid monthly what would your gross pay be each pay period
vichka [17]
Come buddy you got this , Just divide 33500 / 12 Months = 2,791.66667
3 0
3 years ago
Find the circumference of the circle shown. Round to the nearest tenth.
Sunny_sXe [5.5K]

Answer:

110 cm

Step-by-step explanation:

So if we know the diameter, which is 35 cm, we can use the formula π*d. So we would take the diameter and put it in the place of d. So it would be pie times 35. Which would result in us getting 109.96. And this rounded to the nearest tenth would be 110. So The circumference would be 110 cm.

5 0
3 years ago
To prove :One plus cot square theta into tan theta by sec square theta = cot theta
pickupchik [31]

we are given

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)

We will simplify left side and make it equal to right side

Left side:

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}

we can use trigonometric identity

1+cot^2(\theta)=csc^2(\theta)

we can replace it

\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}

now, we know that

tan =sin/cos

\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}

we can simplify it

and we get

\frac{cos(\theta)}{sin(\theta)}

we can also write it as

=cot(\theta)

Right Side:

cot(\theta)

we can see that

left side = right side

so,

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)......Answer

6 0
3 years ago
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