Answer:
i think it's c but I'm rly not sure on this one...
Answer:
x>14
Step-by-step explanation:
X-3> 11
Add 3 to each side
X-3+3> 11+3
x > 14
The hole is open at 14 since it is greater than
( it would be closed if it were ≥) The line goes to the right since it is greater than
2*5=10 (the measure of one long side is 10)
3*4=12 (the measure of one wide side is 12)
A box has four sides to the perimeter of the flat wrapping paper must consist of four edges. Because we know that one edge is 10 inches long and another side is 12 inches wide we assume that the corresponding sides are equal.
So now we know that we have two sides that are 10 inches and 2 sides that are 12 inches.
10+10+12+12= 44 inches
Answer and step-by-step explanation:
We learn that (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3
So in this case, it would be:
= x^3 + (3*x^2*2) + (3*x*2^2) + 2^3
= x^3 + 6x^2 + 3x * 4 + 8
= x^3 + 6x^2 + 12x + 8
This is the standard form of the equation
Hope it help you :3