define a variable write an equation and solve the problem. the length of a rectangle is twice the width. an equation that models
1 answer:
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Step-by-step explanation:
<u>Formula</u><u> </u><u>U</u><u>s</u><u>e</u><u>d</u>
<u>By distance formula,</u>
- d (A,B)=√[(x₁ - x₂)² + (y₁ - y₂)²]
Answer:
E is not a subspace of
Step-by-step explanation:
E is not a subspace of
In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.
Consider
(a,b) = (1,1)
(c,d) = (-1,-1)
It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.
But (a,b) + (c,d) = (1-1, 1-1) = (0,0)
and (0,0) is not in E.
By the way, it can be proved that in any vector space all sub spaces must have the vector zero.