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laila [671]
3 years ago
14

A woman put $580 into a savings account for one year. The

Mathematics
1 answer:
amm18123 years ago
3 0

Answer:

$34.80

Step-by-step explanation:

580(1.06)^1

614.8

614.8-580

$34.80

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Does the given ordered pair, (-3,5/2) satisfies the given equation. 5x-2y=5 ?
anzhelika [568]

Answer:

No, it does not.

5 0
3 years ago
PLEASE HELP!! 50 POINTS!!!!!
OLEGan [10]

Answer:

3\2 is the marked

y cos x,=2

3\2=0.5

x=0.5*2=3.0

=3.0*2=6.0

6 0
2 years ago
(1.1.8 in the book) Let P be the proposition ’I bought a lottery ticket this weekend’ and Q be the proposition ’I won the millio
Karolina [17]

Answer:

~ is for negation

^ is for "and"

v is for "or"

=> for "if then"

<=> for "if and only if"

Step-by-step explanation:

(a) ~P (negation of P)

I didn't buy a lottery ticket this weekend.

(b) P v Q (P is in disjunction Q)

I have either bought a lottery ticket this weekend or won the million dollar jackpot.

(c) P => Q (Q is a consequence of P)

I won the million dollar jackpot because I bought a lottery ticket this weekend.

(d) P ^ Q (P is in conjunction with Q)

I bought a lottery ticket this weekend, and I won the million dollar jackpot.

(e) P <=> Q (P and Q are dependent on each other)

If only I had bought a lottery ticket this weekend, I would have won the million dollar jackpot.

(f) ~P => ~Q (negation of Q is a consequence of negation of P)

I didn't win the million dollar jackpot because I didn't buy a lottery ticket this weekend.

(g) ~P ^ ~Q (negation of P is in conjunction with negation of Q)

I neither bought a lottery ticket this weekend nor won the million dollar jackpot.

(h) ~P v (P ^ Q)

This is logically equivalent to (~P v P) ^ (~P v Q) (negation of P is in disjunction with P, and also with disjunction with Q), and can be best expressed as:

It didn't matter that I bought a jackpot ticket or not, I won the million dollar jackpot.

8 0
3 years ago
Which two values of x are roots of the polynomial below?
Julli [10]

Answer:

B. and C.

Step-by-step explanation:

1. Set the polynomial equal to zero:

x² + 5x + 7 = 0

2. Plug the given values of a, b, and c into the quadratic formula:

x=\frac{-5+-\sqrt{5^{2}-4(1)(7) } }{2(1)}

3. Solve the square root:

x=\frac{-5+-\sqrt{25-4(1)(7)} }{2(1)}

x=\frac{-5+-\sqrt{25-28} }{2(1)}

x=\frac{-5+-\sqrt{-3} }{2(1)}

4. Simplify the rest:

x=\frac{-5+-\sqrt{-3} }{2}

5. Separate the solutions:

x=\frac{-5+\sqrt{-3} }{2}  , x=\frac{-5-\sqrt{-3} }{2}

Thus, options B and C are the answers.

hope this helps!

4 0
2 years ago
Three friends earned more than $200 washing cars they pay their parents $20 for supplies and divided the rest of the money equal
kow [346]
$90 because 200-10=180 and divide 180 by 2 which is 90.
3 0
3 years ago
Read 2 more answers
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