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3 years ago

Solve for c.

Mathematics

2 answers:

sveticcg [70]3 years ago

5 0

Answer: the correct option is

(D) $c=\dfrac{d+ab}{a}.$

Step-by-step explanation: We are given to solve the following equation for the value of c :

$a(c-b)=d~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To solve the given equation for c, we need to take c on one side and all other values on the other side of the equation.

The solution for c of equation (i) is as follows :

$a(c-b)=d\\\\\Rightarrow ac-ab=d\\\\\Rightarrow ac=d+ab\\\\\Rightarrow c=\dfrac{d+ab}{a}.$

Thus, the required value of c is $c=\dfrac{d+ab}{a}.$

Option (D) is CORRECT.

ICE Princess25 [194]3 years ago

3 0

a(c−b)=d
ac - ab = d
ac = d + ab
c = (d + ab) / a

answer is
D. c = (d + ab) / a

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Answer:

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Step-by-step explanation:

Given

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Required

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First, convert the given time to minutes

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$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

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$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

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2 years ago

Help

Vedmedyk [2.9K]

By pythagoreans' theorem,

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3 years ago

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Answer:

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Step-by-step explanation:

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