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alexdok [17]
3 years ago
9

Why does one of the ratios in a percent proportion always have a denominator of 100?

Mathematics
2 answers:
zzz [600]3 years ago
7 0

Answer:

Ratios in a percent proportion always have a denominator of 100 because 100 % is the whole

Step-by-step explanation:


BaLLatris [955]3 years ago
3 0

Answer:


Step-by-step explanation:

hi my name is sarah thats sarah with an h to bad im not going to hate cause haters gonna hate my step dad gary.

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1/5 × 3 + 1/5 = y

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Hi I hope you are all okay could someone help me with this math question thankyou !!!
earnstyle [38]

Answer:

x = 49

Step-by-step explanation:

Given the mathematical expression and data;

y = 1/√x

y = 7 and x = 64

First of all, we would find the constant of proportionality, k;

y = k/√x

7 = k/√64

7 = k/8

k = 7 * 8

k = 56

Next, to find the value of x, when y = 8

y = k/√x

Substituting the values, we have;

8 = 56/√x

Cross-multiplying, we have;

8 * √x = 56

√x = 56/8

√x = 7

Taking the square of both sides, we have;

(√x)² = 7²

x = 49

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3 years ago
A glider begins its descent 3/5​​ mile above the ground. After 30 minutes, it is 9/20​​ mile above the ground. If it continues t
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Answer:

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Step-by-step explanation:

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2 years ago
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Harlamova29_29 [7]

Answer:

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Step-by-step explanation:

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In an effort to estimate the mean amount spent per customer for dinner at a major Atlanta restaurant, data were collected for a
Softa [21]

Answer:

95% Confidence interval = (23.4,26.2)

Step-by-step explanation:

In this problem we have to develop a 95% CI for the mean.

The sample size is n=49, the mean of the sample is M=24.8 and the standard deviation of the population is σ=5.

We know that for a 95% CI, the z-value is 1.96.

The CI is

M-z*\sigma/\sqrt{n}\leq\mu\leq M+z*\sigma/\sqrt{n}\\\\24.8-1.96*5/\sqrt{49}\leq\mu\leq 24.8+1.96*5/\sqrt{49}\\\\ 24.8-1.4\leq\mu\leq 24.8+1.4\\\\23.4\leq\mu\leq 26.2

5 0
3 years ago
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