All categories

3 years ago

What are the smallest and largest possible numbers in base 3?

1 answer:

3 0

Our number system is in base 10. The ones place holds digits 0 - 9. When you reach 10, you must add another place value (the tens place).

Base 3 is digits 0-2 becasue when you reach 3, you need to add another place value.

Therefore, the smallest number is 0 and the largest number is 2.

Answer: smallest = 0, largest = 2

You might be interested in

A.3.5 B.-2.5 C.-5.5 D.2.5

mart [117]

The answer is 2.5 because the point is on -1.5, so -1.5+4=2.5

7 0

3 years ago

What is -4x<8. I’m a little confused.

svetoff [14.1K]

Answer:

x > -2

Step-by-step explanation:

6 0

3 years ago

Could I solve this inequality by completing the square? How would I do so?

sammy [17]

Answer:

$\large\boxed{x>-2+\sqrt{14}\ \vee\ x$

Step-by-step explanation:

$x^2+4x>10\\\\x^2+2(x)(2)>10\qquad\text{add}\ 2^2=4\ \text{to both sides}\\\\x^2+2(x)(2)+2^2>10+4\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(x+2)^2>14\Rightarrow x+2>\sqrt{14}\ \vee\ x+2-2+\sqrt{14}\ \vee\ x$

8 0

3 years ago

A machine fills containers with 35 ounces of raisins. After the containers are filled, another machine weighs them. If the conta

EleoNora [17]

Answer:

a think only thing thats close to my data

Step-by-step explanation:

7 0

2 years ago

A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o

vivado [14]

Since $\rho=\dfrac mV$ (density = mass/volume), we can get the mass/weight of the liquid by integrating the density $\rho(x,y,z)$ over the interior of the tank. This is done with the integral

$\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx$

which is more readily computed in cylindrical coordinates as

$\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}$

7 0

3 years ago