The first-serve percentage of a
tennis player in a match is normally distributed with a standard deviation of
4.3%. If a sample of 15 random matches of
the player is taken, the mean
first-serve percentage is found to be 26.4%. The margin of error of the sample
mean is 83.71%.
Answer:
They are doing OK some are getting answers and some are not like me. For some people don't even know what they're asking.
Answer:
V=14
Step-by-step explanation:
3v=42 divide both sides by 3. getting v=14
