11.
so we do 40 / 3.667 (3 and 2/3, as far as i can tell) to get x.
so it's 10.9, or 11.
Answer:
a. 97.72%
Step-by-step explanation:
The weights of boxes follows normal distribution with mean=28 ounce and standard deviation=0.9 ounces.
a. We have to calculated the percentage of the boxes that weighs more than 26.2 ounces.
Let X be the weight of boxes. We have to find P(X>26.2).
The given mean and Standard deviations are μ=28 and σ=0.9.
P(X>26.2)= P((X-μ/σ )> (26.2-28)/0.9)
P(X>26.2)= P(z> (-1.8/0.9))
P(X>26.2)= P(z>-2)
P(X>26.2)= P(0<z<∞)+P(-2<z<0)
P(-2<z<0) is computed by looking 2.00 in table of areas under the unit normal curve.
P(X>26.2)=0.5+0.4772
P(X>26.2)= 0.9772
Thus, the percent of the boxes weigh more than 26.2 ounces is 97.72%
Answer:
-83%
Step-by-step explanation:
The percentage change can be found using the formula ...
percentage change = ((new value)/(old value) -1) × 100%
= (17/100 -1) × 100%
= -83/100 × 100%
= -83% . . . . . % change from 100 to 17
