2
Step-by-step explanation:
-2 -2/ -3+1 = -4/-2 = 2
you just have to use the slope formula
<span>To do that, you need to set it all to zero and factor:
x^2+8x+15 = 0
(x+5)(x+3) = 0
then put both those in parentheses chunks in their own equations
x + 5 = 0
x + 3 = 0
and then simplify
x = -5
x = -3
So the two points where the parabola crosses the x-axis are -5 and -3.</span>
Answer:
X=85.78, because we have angle side
Answer:
![C_{22} = 389](https://tex.z-dn.net/?f=C_%7B22%7D%20%3D%20389)
![Max(A_{31}) =376](https://tex.z-dn.net/?f=Max%28A_%7B31%7D%29%20%3D376)
Step-by-step explanation:
Given
See attachment for complete question
Solving (a): The entry C22
First, matrix C represents the inventory at the end of July.
The entry of C is calculated as:
![C = Inventory - Sales](https://tex.z-dn.net/?f=C%20%3D%20Inventory%20-%20Sales)
i.e.
![C = \left[\begin{array}{ccc}543&356&643\\364&476&419\\376&903&409\end{array}\right] - \left[\begin{array}{ccc}102&78&97\\98&87&59\\54&89&79\end{array}\right]](https://tex.z-dn.net/?f=C%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D543%26356%26643%5C%5C364%26476%26419%5C%5C376%26903%26409%5Cend%7Barray%7D%5Cright%5D%20%20-%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D102%2678%2697%5C%5C98%2687%2659%5C%5C54%2689%2679%5Cend%7Barray%7D%5Cright%5D)
![C = \left[\begin{array}{ccc}543-102&356-78&643-97\\364-98&476-87&419-59\\376-54&903-89&409-79\end{array}\right]](https://tex.z-dn.net/?f=C%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D543-102%26356-78%26643-97%5C%5C364-98%26476-87%26419-59%5C%5C376-54%26903-89%26409-79%5Cend%7Barray%7D%5Cright%5D)
![C = \left[\begin{array}{ccc}441&278&546\\266&389&360\\322&814&330\end{array}\right]](https://tex.z-dn.net/?f=C%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D441%26278%26546%5C%5C266%26389%26360%5C%5C322%26814%26330%5Cend%7Barray%7D%5Cright%5D)
Item C22 means the entry at the second row and the second column.
From the matrix
![C_{22} = 389](https://tex.z-dn.net/?f=C_%7B22%7D%20%3D%20389)
Solving (b): The maximum A31 possible.
From the given data, we have:
![Inventory = \left[\begin{array}{ccc}543&356&643\\364&476&419\\376&903&409\end{array}\right]](https://tex.z-dn.net/?f=Inventory%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D543%26356%26643%5C%5C364%26476%26419%5C%5C376%26903%26409%5Cend%7Barray%7D%5Cright%5D)
![Unit\ Sales = \left[\begin{array}{ccc}102&78&97\\98&87&59\\54&89&79\end{array}\right]](https://tex.z-dn.net/?f=Unit%5C%20Sales%20%3D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D102%2678%2697%5C%5C98%2687%2659%5C%5C54%2689%2679%5Cend%7Barray%7D%5Cright%5D)
From the matrices above.
A31 means entry at the 3rd row and 1st column.
So, the possible values of A31 are:
![A_{31} = 376](https://tex.z-dn.net/?f=A_%7B31%7D%20%3D%20376)
and
![A_{31} = 54](https://tex.z-dn.net/?f=A_%7B31%7D%20%3D%2054)
By comparison, 376 > 54
So: