Question

Please help and thank you

Answer 1

Answer:

A. 8, 16, 32, 64....

Step-by-step explanation:

to solve, we can plug in the numbers 1, 2, 3, and 4 for the letter n in the equation. we got these numbers since the problem is asking us for the first 4 numbers in the sequence

$a_n = 4 × 2^n$

$a_1 = 4 × 2^1$ = 4 × 2 = 8

$a_2 = 4 × 2^2$ = 4 × 4 = 16

$a_3 = 4 × 2^3$ = 4 × 8 = 32

$a_4 = 4 × 2^4$ = 4 × 16 = 64

so the first four terms in the sequence are 8, 16, 32, and 64, which is choice A

Answer 2

A. 8, 16, 32, 64 ...

Hope this helps!! <3