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3 years ago

A line passes through (4, 5) and (8, 9). Which equation best represents the line?

Mathematics

2 answers:

geniusboy [140]3 years ago

6 0

Y=x+1 is the anwser
to the question

S_A_V [24]3 years ago

4 0

Here, Coordinates: (4, 5) & (8, 9)
Calculation of Slope, m = y2-y1 / x2-x1
m = 9-5 / 8-4
m = 4 / 4
m = 1

Now, Take any coordinate:
y - y1 = m(x - x1)
y - 5 = 1(x - 4)
y - 5 = x - 4
y = x + 1

In short, Your Answer would be: y = x + 1

Hope this helps!

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Please Help! I will give you a lot of points!

Alexandra [31]

Answer:i can see it

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the height of a rectangular prism with a 3 in by 4 in base and a volume of 20 cubic inches

Crank

Answer:

1 2/3 inches.

Step-by-step explanation:

Volume = area of the base * height so:

20 = 3*4 * h

h = 20/12

h = 1 2/3 inches.

5 0

3 years ago

How do you work this out?

Helen [10]

Answer:

£365

Step-by-step explanation:

so add another column and call it midpoint. use the weekly earnings column to find the midpoints add both numbers then divide by 2

then times all these numbers by the corresponding frequencies

1 * 200=200

11 * 300=3300

5 * 400=2000

0 * 500=0

3 * 600=1800

then add these numbers =7300 then do 7300/20=365

5 0

3 years ago

(11-8)x3+7+27-3 (18÷3)+6+(14-8)x5 (11-7)x6+4+32-4

horsena [70]

The results of the arithmetic evaluations as given in the task content are; 40,42 and 62.

<h3>What are the results of the arithmetic evaluations?</h3>

The arithmetic operations above can be evaluated and simplified as follows;

(11-8)x3+7+27-3 = (3×3)+7+27-3 = 40.

(18÷3)+6+(14-8)x5 = (6)+6+(6)x5 = 42.

(11-7)x6+4+32-4 = (5×6) +4 +32-4 = 62.

Read more on arithmetic evaluations;

brainly.com/question/4694189

#SPJ1

8 0

2 years ago

If P and Q are two sets then n( P-Q) means ?

Lapatulllka [165]

$\huge{\mathbb{ \tt{ANSWER}}}$

I shall use the symbol U for union

^ for intersection

~ for complement

The property of set subtraction states that for any sets X and Y, X-Y = X ^ Y~

That is in words, X throw away Y is the same as the intersection of X and the complement of Y

or X and anything NOT in Y

At the SET level, the proof looks like this:

(P-Q) U (Q-P) = « given

(P^Q~) U (Q ^ P~) = « property of set subtraction

(P U Q) ^ (P U P~) ^ (Q~ U Q) ^ (Q~ U P~) = « distributive property

(P u Q) ^ (Q~ U P~) = « Union of any set with it's complement is the universal

set which gets dropped by any intersection of a non-universal set

(P u Q ) ^ (Q ^ P)~ = « De Morgan's Law

(P u Q) - (Q ^ P) = « property of set subtraction

(P u Q) - (P ^ Q) « commutative property

At the ELEMENT level, the proof looks like this:

» Proves left side is subset of right side

If x is in (P-Q) U (Q-P) then x is in (P-Q) OR x is in (Q-P)

If x is in P-Q then x is in P but not in Q.

Then X is in P U Q.

Since x is not in Q, x is NOT in P ^ Q

Hence x is in P U Q but NOT in P^Q, which

means it is an element if (P U Q) - (P ^ Q)

Therefore x is an element of the set defined by the right side, which means (P-Q) U (Q-P) is a subset of (P U Q) - (P ^ Q)

« proves right side is subset of the left side

If x is an element of (P U Q) - (P ^ Q) then

x is in (P U Q) but NOT in (P^Q)

Since x is in P U Q, x is in P OR x is in Q.

Since x is NOT in (P^Q) then x is NOT in BOTH P and Q.

Hence x is in either P or Q but not both.

If x is in P, then x is not in Q, so x is in P-Q.

Therefore x is in (P-Q) U (Q-P).if x is in Q, then x is not in P, so x is in Q-P.Therefore x is in (Q-P) U (P-Q).There x is an element of set defined by the left side, which menas (P u Q)-(P ^Q) is a subset of (P-Q) U (Q-P).

#CarryOnLearning

#LetsEnjoyTheSummer

8 0

3 years ago