14+4k=2−2k solve for k

Pls help will mark as brainliest

ASHA 777 [7]

Answer:

Step-by-step explanation:

8 0

3 years ago

7. In name the bisected angles 1 and 2. If is 4x  3y, can be determined in terms of x and y? If so, state in terms of x+ y expr

Ugo [173]

Answer:since there is no diagram i will answer to the best of my ability.

Step-by-step explanation:

If an angle is bisected then it is divided into 2 equal angles which i think they are naming 4x and 3y. In this case, 4x=3y. Solving for x, we get x= (3y)/4. Solving for y we get y= (4x)/3. Now if we substitute (4x)/3 for y in the equation x= (3y)/4 then x= (3(4x)/3)/4 = 4x/4=× so then we can say x÷y = measure of original angle that was bisected. Or znother way it can be said is x+y = 2x or x+ y =2y.

8 0

2 years ago

In △ABC, AB = 13.2m,

luda_lava [24]

Answer:

(i) ∠ABH = 14.5°

(ii) The length of AH = 4.6 m

Step-by-step explanation:

To solve the problem, we will follow the steps below;

(i)Finding ∠ABH

first lets find <HBC

<BHC + <HBC + <BCH = 180° (Sum of interior angle in a polygon)

46° + <HBC + 90 = 180°

<HBC+ 136° = 180°

subtract 136 from both-side of the equation

<HBC+ 136° - 136° = 180° -136°

<HBC = 44°

lets find <ABC

To do that, we need to first find <BAC

Using the sine rule

$\frac{sin A}{a}$ = $\frac{sin C}{c}$

A = ?

a=6.9

C=90

c=13.2

$\frac{sin A}{6.9}$ = $\frac{sin 90}{13.2}$

sin A = 6.9 sin 90 /13.2

sinA = 0.522727

A = sin⁻¹ ( 0.522727)

A ≈ 31.5 °

<BAC = 31.5°

<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)

31.5° +<ABC + 90° = 180°

<ABC + 121.5° = 180°

subtract 121.5° from both-side of the equation

<ABC + 121.5° - 121.5° = 180° - 121.5°

<ABC = 58.5°

<ABH = <ABC - <HBC

=58.5° - 44°

=14.5°

∠ABH = 14.5°

(ii) Finding the length of AH

To find length AH, we need to first find ∠AHB

<AHB + <BHC = 180° ( angle on a straight line)

<AHB + 46° = 180°

subtract 46° from both-side of the equation

<AHB + 46°- 46° = 180° - 46°

<AHB = 134°

Using sine rule,

$\frac{sin 134}{13.2}$ = $\frac{sin 14.5}{AH}$

AH = 13.2 sin 14.5 / sin 134

AH≈4.6 m

length AH = 4.6 m

8 0

2 years ago

Mason has a collection of .49 stamps, .20 stamps and .3 stamps worth 23.55. He has 56 total .49 and .20 stamps and the number of

Nezavi [6.7K]

Answer: Mason has 40 forty-nine cent stamps, 16 twenty cent stamps and 25 three cent stamps

Step-by-step explanation:

Let x represent the number of 49 cent stamps that Mason has.

Let y represent the number of 20 cent stamps that Mason has.

Let z represent the number of 3 cent stamps that Mason has.

Mason has a collection of 49 cent stamps, 20 cent stamps, and 3 cent stamps worth $23.55. This means that

0.49x + 0.2y + 0.03z = 23.55 - - - - -1

He had 56 total 49 cent and 20 cent stamps. This means that

x + y = 56

x = 56 - y

The number of 3 cent stamps is nine more than the number of 20 cent stamps. This means that

z = y + 9

Substituting x = 56 - y and z = y + 9 into equation 1, it becomes

0.49(56 - y) + 0.2y + 0.03(y + 9) = 23.55

27.44 - 0.49y + 0.2y + 0.03y + 0.27 = 23.55

27.44 + 0.27 - 0.49y + 0.2y + 0.03y = 23.44

27.71 - 0.26y = 23.55

- 0.26y = 23.55 - 27.71

- 0.26y = - 4.16

y = - 4.16/ - 0.26y

y = 16

x = 56 - y = 56 - 16

x = 40

z = y + 9 = 16 + 9

z = 25

7 0

2 years ago

Find f(-5) f(x) = -4x + 3 A) -17 B) -7 C) 12 D) 23

Andrew [12]

Answer:

B

Step-by-step explanation:

=tyhgff GJ jhvcvvbvcccvjuuuu hgfdvghg jhvgfgg bbvcfff bbvcfff bbvcfff hbbjggg hhfccgyhb 5th and 3rd of November in a rectangle has been released in December 5th of July in a square of the area and I am very interested to the area and I look for the position and am looking forward for the position of your firm in my work to be a great fit and would love ms your help and if I could help with any other things

3 0

2 years ago