Answer:
<em>C. 1/(4^10)</em>
Step-by-step explanation:
<h2>Let's break it down: 4^-2 = 1/(4^2)</h2><h2>(1/(4^2))^5 = (1^5)/(4^2)^5 = 1/(4^10)</h2>
Let's separate this problem into several parts:
1. The product of x
AND
2. The sum of 6 and 8
TIMES
3. The square of x
So translating this word problem into numbers, we have:
x TIMES (6+8) TIMES x²
so that is:
x * 14 * x²
which is:
14x^(2+1) = 14x³
Using it's concepts, it is found that for the function
:
- The vertical asymptote of the function is x = 25.
- The horizontal asymptote is y = 5. Hence the end behavior is that
when
.
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity. They also give the end behavior of a function.
In this problem, the function is:

For the vertical asymptote, it is given by:
x - 25 = 0 -> x = 25.
The horizontal asymptote is given by:

More can be learned about asymptotes at brainly.com/question/16948935
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3√10^4x is equivalent to -√10 3/4^x and -4√10^3x they are all equivalent
Answer:
Free points...?
Step-by-step explanation: