About 175 ninth grade boys. 2/25 is equal to 0.08. if we take the 14 students and divide it by 0.08, we can get the total of 175 ninth grade boys.
Answer:
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Step-by-step explanation:
Total plants = 11
Domestic plants = 7
Outside the US plants = 4
Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:
P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ
where n = total no. of trials
x = no. of successful trials
p = probability of success
q = probability of failure
Here we have n=4, p=4/11 and q=7/11
P(X≥1) = 1 - P(X<1)
= 1 - P(X=0)
= 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰
= 1 - 0.16399
P(X≥1) = 0.836
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Answer:
square
Step-by-step explanation:
The opposite angles are congruent, the diagonals bisect each other, the opposite sides are parallel, the diagonals bisect the angles
For a 45-45-90 angle the hypotenuse is s * square root of 2
so the hypotenuse is 14 * square root of 2 or 19.8
:)))
