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TEA [102]
3 years ago
13

What is the value of the remainder if 10x4 – 6x3 + 5x2 – x + 1 is divided by x – 3?

Mathematics
2 answers:
natita [175]3 years ago
8 0

Answer:

Remainder is 691.

Step-by-step explanation:

Given function is 10x^4-6x^3+5x^2-x+1.

Now we need to find remainder if we divide given function 10x^4-6x^3+5x^2-x+1 by (x-3)

(x-3) means plug x=3 into 10x^4-6x^3+5x^2-x+1 to find remainder.

10x^4-6x^3+5x^2-x+1

=10(3)^4-6(3)^3+5(3)^2-(3)+1

=10(81)-6(27)+5(9)-(3)+1

=810-162+45-3+1

=856-162-3

=856-165

=691

Hence remainder is 691.

PIT_PIT [208]3 years ago
3 0

Answer:

The remainder = 691

Step-by-step explanation:

Let p(x) = 10x⁴ - 6x³ + 5x² - x + 1

We have to divide p(x) by (x - 3)

To find the remainder we  have to find p(3)

<u>To find the remainder</u>

p(x) = 10x⁴ - 6x³ + 5x² - x + 1

p(3) = 10 * (3)⁴ - 6*(3)³ + 5* (3)² - 3 + 1

 = (10 * 81 ) - ( 6 * 27 ) + (5 * 9) - 3 + 1

 = 810 - 162 + 45 - 3 + 1 = 691

Therefore the remainder is 691

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