Question

What is the value of the remainder if 10x4 – 6x3 + 5x2 – x + 1 is divided by x – 3?

Answer 1

Answer:

Remainder is 691.

Step-by-step explanation:

Given function is $10x^4-6x^3+5x^2-x+1$.

Now we need to find remainder if we divide given function $10x^4-6x^3+5x^2-x+1$ by (x-3)

(x-3) means plug x=3 into $10x^4-6x^3+5x^2-x+1$ to find remainder.

$10x^4-6x^3+5x^2-x+1$

$=10(3)^4-6(3)^3+5(3)^2-(3)+1$

$=10(81)-6(27)+5(9)-(3)+1$

$=810-162+45-3+1$

$=856-162-3$

$=856-165$

$=691$

Hence remainder is 691.

Answer 2

Answer:

The remainder = 691

Step-by-step explanation:

Let p(x) = 10x⁴ - 6x³ + 5x² - x + 1

We have to divide p(x) by (x - 3)

To find the remainder we  have to find p(3)

To find the remainder

p(x) = 10x⁴ - 6x³ + 5x² - x + 1

p(3) = 10 * (3)⁴ - 6*(3)³ + 5* (3)² - 3 + 1

 = (10 * 81 ) - ( 6 * 27 ) + (5 * 9) - 3 + 1

 = 810 - 162 + 45 - 3 + 1 = 691

Therefore the remainder is 691