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Wewaii [24]
4 years ago
11

Can someone help me with the answer

Mathematics
1 answer:
stepan [7]4 years ago
8 0

A is the correcto answer

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Choose the isosceles triangles.
mixas84 [53]

Answer:

<h2><u><em>the second one.</em></u></h2>

Step-by-step explanation:

5 0
4 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
diamong [38]

Answer:

 A-2, B-DNE*, C-3, D-DNE, E-4, F-1

---------------------

The first attachment shows the solutions to A and C.

The second attachment shows the solutions to E and F.

There are no real number solutions to systems B and D.

_____

In general, you can solve the linear equation for y, then substitute that into the quadratic. You can subtract the x-term on the left and complete the square to find the solutions.

A.

 (3-x) +12 = x^2 +x

 15 = x^2 + 2x

 16 = x^2 +2x +1 = (x +1)^2 . . . . add the square of half the x-coefficient to complete the square; next take the square root

 ±4 -1 = x = {-5, 3) . . . . . identifies the second solution set for system A

__

B.

 (x -1) -15 = x^2 +4x

 -16 = x^2 +3x

 -13.75 = x^2 +3x +2.25 = (x +1.5)^2

roots are complex: -1.5 ±i√13.75

__

C.

 (1-2x) +5 = x^2 -3x

 6 = x^2 -x

 6.25 = x^2 -x + .25 = (x -.5)^2

 ±2.5 +.5 = x = {-2, 3} . . . . . identifies the third solution set for system C

__

remaining problems are done in a similar way.

_____

* DNE = does not exist. There is no matching solution set for the complex numbers that are the solutions to this.

---------------------

<em>Hope this helps!</em>

<em />

<u>Brainliest would be great!</u>

<u />

---------------------

<em><u>With all care,</u></em>

<em><u>07x12!</u></em>

4 0
4 years ago
Alice, Benjamin, and Carol each try independently to win a carnival game. If their individual probabilities for success are 1/5,
sweet-ann [11.9K]

Answer:

The correct option is E.

Step-by-step explanation:

It is given that Alice, Benjamin, and Carol each try independently to win a carnival game.

Let A, B and C represent the following events.

A = Alice win

B = Benjamin win

C = Carol win

P(A)=\frac{1}{5} and P(A')=1-P(A)=1-\frac{1}{5}=\frac{4}{5}

P(B)=\frac{3}{8} and P(B')=\frac{5}{8}

P(C)=\frac{2}{7} and P(C')=\frac{5}{7}

We need to find the probability that exactly two of the three players will win but one will lose.

Probability=P(A\cap B\cap C')+P(A\cap B'\cap C)+P(A'\cap B\cap C)

Probability=P(A)P(B)P(C')+P(A)P(B')P(C)+P(A')P(B)P(C)

Probability=\frac{1}{5}\cdot\frac{3}{8}\cdot\frac{5}{7}+\frac{1}{5}\cdot\frac{5}{8}\cdot\frac{2}{7}+\frac{4}{5}\cdot\frac{3}{8}\cdot\frac{2}{7}

Probability=\frac{3}{56}+\frac{1}{28}+\frac{3}{35}

Probability=\frac{7}{40}

The probability that exactly two of the three players will win but one will lose is \frac{7}{40}.

Therefore the correct option is E.

6 0
4 years ago
Please help with this question!!!!!
Finger [1]
72 in2 because you add the area of everything
5 0
3 years ago
What is 63.48 rounded off to 1 decimal place?
Lilit [14]

Answer:

63.5

Step-by-step explanation:

5 0
4 years ago
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