Which of the following statements is true about the distribution

Mama L [17]

" Given f (x) = 3x + 2 and g(x) = 4 – 5x, find (f + g)(x), (f – g)(x), (f × g)(x), and (f / g)(x).1. = [3x + 2] + [4 – 5x] = 3x + 2 + 4 – 5x. = 3x – 5x + 2 + 4. = –2x + 6. (f – g)(x) 2. = f (x) – g(x)= [3x + 2] – [4 – 5x] = 3x + 2 – 4 + 5x. = 3x + 5x + 2 – 4. = 8x– 2. 3. ...= (3x + 2)(4 – 5x) = 12x + 8 – 15x2 – 10x. = –15x2 + 2x + 8. " - Google

3 0

2 years ago

Birth Weights Babies born after a gestation period of 32-35 weeks have a mean weight of 2600 grams and a standard deviation of 6

lukranit [14]

Answer:

The z-score for the 34-week gestation period baby is 0.61

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ,

where x is the raw score,

μ is the population mean

σ is the population standard deviation.

We are told in the question that:

Babies born after a gestation period of 32-35 weeks have a mean weight of 2600 grams and a standard deviation of 660 grams. Also, we are supposing a 34-week gestation period baby weighs 3000grams

The z-score for the 34-week gestation period baby is calculated as:

z = (x-μ)/σ

x = 3000, μ = 2600 σ = 660

z = 3000 - 2600/660

= 400/660

=0.6060606061

Approximately, ≈ 0.61

6 0

2 years ago

A coin is tossed 4 times. Which of the following represents the probability of the coin landing on heads all 4 times?

galben [10]

Answer:

C.1/16

Step-by-step explanation:

When a coin is tossed 4 times, the number of outcomes are:

2^4 = 16

So,

From the outcomes, only one outcome will be when there will be all heads

So, the probability will be:

One out of the 16 outcomes

Hence, the probability of a coin landing on heads all 4 times is:

C.1/16

5 0

2 years ago

LCM of x<sup>2</sup>+5x+6 and x<sup>2</sup>-x-6 is ………………………

sergejj [24]

Answer:

$(x^2 - 9)(x + 2)$

Step-by-step explanation:

Given:

$x^2 + 5x + 6$

$x^2 - x - 6$

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

$x^2 + 5x + 6$

$x^2 + 3x + 2x + 6$

$(x^2 + 3x) + (2x + 6)$

$x(x + 3) + 2(x + 3)$

$(x + 2)(x + 3)$

$x^2 - x - 6$

$x^2 - 3x +2x - 6$

$x(x - 3) + 2(x - 3)$

$(x + 2)(x - 3)$

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

$x^2 + 5x + 6 = (x + 2)(x + 3)$

$x^2 - x - 6 = (x + 2)(x - 3)$

The common factors would be: =>

$(x + 2)$ (this is common in both polynomials, so we would take just one of them as a factor.

$(x + 3)$ and,

$(x - 3)$

Their product = $(x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2)$

4 0

3 years ago

Julian is using a biking app that compares his position to a simulated biker traveling Julian's target speed. When Julian is beh

zepelin [54]

Answer:

$\large \boxed{\text{11 km/h}}$

Step-by-step explanation:

1. The situation after 15 min:

(a) Distance travelled by simulated biker:

15 min =¼ h

$\text{Distance} = \dfrac{1}{4}\text{ h} \times \dfrac{\text{20 km}}{\text{1 h}} = \text{5 km}$

(b) Distance travelled by Julian

Julian is 2¼ km behind the biker. The distance he has travelled is (5 - 2¼) km

5 - 2¼ = 5 - ⁹/₄ = ²⁰/₄ - ⁹/₄ = ¹¹/₄ = 2¾

Julian has travelled 2¾ km in ¼ h.

2. Julian's average speed

$\text{Speed} = \dfrac{\text{Distance}}{\text{Time}} = \dfrac{2\frac{3}{4}\text{ km}}{\frac{1}{4}\text{ h}} =\dfrac{11}{4}\text{ km}\times \dfrac{4}{\text{1 h}} = \textbf{11 km/h}\\\\\text{Julian's average speed is $\large \boxed{\textbf{11 km/h}}$}$

7 0

2 years ago

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