<u><em>Answer:</em></u>
A. $4397.9
<u><em>Explanation:</em></u>
We are given that Kendra sold 200 shares and that the price per share was $22.1
<u>This means that:</u>
Total value = 200 * 22.1 = $4420
Now, we know that the broker charged 0.5% commission on the total value
<u>This means that:</u>
Broker's charge = 0.5% * 4420 = 0.005 * 4420 = $22.1
<u>Therefore,</u>
Kendra's return = Total value - broker's charge
Kendra's return = 4420 - 22.1 = $4397.9
Hope this helps :)
The probability that the mean of a sample of 106 randomly selected humans is lower than 98.5°F is 4.85%
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Z score is given as:
z = (raw score - mean) ÷ (standard deviation/√sample size)
Given mean of 98.6°F, standard deviation is 0.62°F, sample size = 106
For x < 98.5:
z = (98.5 - 98.6) ÷ (0.62÷√106) = -1.66
P(z < -1.66) = 0.0485
The probability that the mean of a sample of 106 randomly selected humans is lower than 98.5°F is 4.85%
Find out more on equation at: brainly.com/question/2972832
#SPJ1
x = 0.25
Step-by-step explanation:
8x = 2
x = 2/8
x = 0.25
Answer:
Option C
Step-by-step explanation:
We are given a coefficient matrix along and not the solution matrix
Since solution matrix is not given we cannot check for infinity solutions.
But we can check whether coefficient matrix is 0 or not
If coefficient matrix is zero, the system is inconsistent and hence no solution.
Option A)
|A|=![\left[\begin{array}{ccc}4&2&6\\2&1&3\\-2&3&-4\end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%262%266%5C%5C2%261%263%5C%5C-2%263%26-4%5Cend%7Barray%7D%5Cright%5D%20%3D0)
since II row is a multiple of I row
Hence no solution or infinite
OPtion B
|B|=![\left[\begin{array}{ccc}2&0&-2\\-7&1&5\\4&-2&0\end{array}\right] \\=2(10)-2(10)=0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%260%26-2%5C%5C-7%261%265%5C%5C4%26-2%260%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2810%29-2%2810%29%3D0)
Hence no solution or infinite
Option C
![\left[\begin{array}{ccc}6&0&-2\\-2&0&6\\1&-2&0\end{array}\right] \\=2(36-2)=68](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%260%26-2%5C%5C-2%260%266%5C%5C1%26-2%260%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2836-2%29%3D68)
Hence there will be a unique solution
Option D
![\left[\begin{array}{ccc}5&10&5\\4&1&4\\-1&-2&-1\end{array}\right] \\=2(10)-2(10)=0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%2610%265%5C%5C4%261%264%5C%5C-1%26-2%26-1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2810%29-2%2810%29%3D0)
=0
(since I row is -5 times III row)
Hence there will be no or infinite solution
Option C is the correct answer
