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Nesterboy [21]
2 years ago
13

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil

e is modeled using the equation h(t) = –16t2 + 48t + 190. Approximately when will the projectile hit the ground? 1.5 seconds 3.2 seconds 5.3 seconds 6.2 seconds
Mathematics
2 answers:
Solnce55 [7]2 years ago
6 0

Answer:

The answer is C

Step-by-step explanation:

Over [174]2 years ago
3 0

Hello! :)

—————— ☆ ☆———————————————————————————-

Answer:

5.3 seconds

Step-by-step explanation:

The answer is 5.3 seconds because

If you solve this equation than you will see how it is 5.3 seconds.

Equation: h (t) = -16t ^ 2 + 48t + 190

Also if you graph it, the answer will be 5.3 seconds

—————— ☆ ☆————————————————————————————

Hope this helps! :)

By: BrainlyMember ^-^

Good luck!

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Answer:

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Which points of the following points are solutions to the equation 3x-4y-8=12
Natali [406]

Answer:

(0, -5), (4, -2), (-16, -17)

Step-by-step explanation:

I attach your full question in the image below

The equation is

3x-4y-8=12

Which can be rewritten as

3x-4y =12 +8

3x-20 = 4y

y = (3/4)*x - 5

We need to check each individual case

(0,-5)

y = (3/4)*(0) - 5  

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(4,-2)

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False

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y = (3/4)*(-16) - 5  

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8 0
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