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brilliants [131]
3 years ago
6

An oak tree is 1.5×1031.5×103 centimeters tall. Which unit of measurement is most appropriate to measure this height?

Mathematics
1 answer:
sdas [7]3 years ago
3 0
If you multiply the amount that you give 1.5 × 1031.5 × 103 the result is 159366.75 centimeters, which is very long to write. For better understanding it is preferable that you write the answer to this multiplication in kilometers. Which would give a result of 1.59 kilometers
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Keith won a cash prize in an art competition. He gave his mother 2/5 of the money he won. Of the remainder, 1/4 was given to his
USPshnik [31]

Answer:

300 dollars

Step-by-step explanation:

Let the original amount = x

x - 2/5x  was what his mother's share looked.

5/5 x - 2/5 x

3/5x is what is left.

3/5 x - 1/4 * 3/5 x - 2/3x * 3/5 = his sister's share and his brothers

3/5x - 1/4*3/5 x - 2/3 * 3/5 = 15

3/5x * (1 - 1/4 - 2/3) = 15

3/5 x 5/60 = 15

15 / 300 * x = 15

1/20  x = 15

x = 15 * 20

x = 300

7 0
2 years ago
N ∆ABC, if sin A = and tan A = , then what is cos A?
leva [86]

Answer:hello :

tanA = sinA/cosA

cosA = sinA /tanA

cosA =(4/5)/(4/3)

cosA=3/5

Step-by-step explanation:

8 0
3 years ago
Help me with this math problem, I need someone to guide me through it I don’t understand what I’m supposed to do first
natita [175]

Answer:

see below

Step-by-step explanation:

The parent function is x^2 which is a parabola at vertex (0,0)

g(x) = ( x+3) ^2

y = f(x + C) C > 0 moves it left  

So the parabola is shifted to the left 3 units

h(x) = -( x+3) ^2

y = −f(x)  

Reflects it about x-axis

Means flip it about the x axis

7 0
3 years ago
Stock A ‘s returns have a standard deviation of 0.5, and stock B’s returns have standard deviation of 0.6.The correlation coeffi
galben [10]

Answer:

The variance of the profile is 0.2179.

Step-by-step explanation:

We are given the following in the question:

\sigma_A = 0.5\\\sigma_B = 0.6\\\rho_{A,B} = 0.5\\w_A = 70\% = 0.7\\w_B = 30\% = 0.3

Variance of portfolio is given by:

w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}

Cov_{A,B} = \rho_{A,B} \times \sigma_A \times \sigma_B \\=0.5\times 0.5 \times 0.6\\=0.15

Putting values, we get,

w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}\\=(0.7)^2(0.5)^2 + (.3)^2(0.6)^2 + 2(0.7)(0.3)(0.15)\\=0.2179

Thus, the variance of the profile is 0.2179.

4 0
3 years ago
Which of these is not a possible r-value?
Tems11 [23]

Answer:

Step-by-step explanation:

A

4 0
3 years ago
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