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3 years ago

Use quadratic formula to find the solutions to the quadratic equation 2x^2-3x+6=0

Mathematics

2 answers:

defon3 years ago

8 0

Answer:

2x² - 3x + 6 = 0

a = 2 b = -3 c = 6

delta = b² - 4ac = 9 - 4.2.6 = -39

$= > x = \frac{3 + \sqrt{39}i }{4} \: or \: x = \frac{3 - \sqrt{39} i}{4}$

raketka [301]3 years ago

8 0

The answer is b!!!!
Good luck

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PLEASE HELP! Since AB=1 and 1=BC, BC=AB by which property?

erastovalidia [21]

Substitution.

Here is an example.

Let x be equal to 3 and y equal to 3.

$x=3, y=3$

From this we can conclude that the values of both x and y are equal to three therefore x and y have the same value and are equal.

$x\wedge y=3\Longrightarrow x=y$

Here in your case we have:

$AB=1, BC=1 \\AB\wedge BC=1\Longrightarrow AB=BC$

Hope this helps.

r3t40

7 0

4 years ago

Solve for x.<br> 11 = 11x

Amanda [17]

Answer:

x=1

Step-by-step explanation:

11=11x

divide

x=11/11

x=1

8 0

3 years ago

Read 2 more answers

The top tree broke and fell over.the remaining tree teunk is 3 feet tall.the tip of the tree rests on the ground 14 feet from th

Bas_tet [7]

Answer:

14.3 feet.

14.3 feet

Step-by-step explanation:

The problem forms a right triangle in which:

The Vertical Leg of the Right Triangle = 3 feet

The Horizontal Leg of the Right Triangle =14 feet

We are to determine the length of the broken part of the tree. This is the Hypotenuse of the Right Triangle,

Using Pythagoras Theorem

$Hypotenuse^2=Opposite^2+Adjacent^2\\Hypotenuse^2=14^2+3^2\\Hypotenuse^2=205\\Hypotenuse=\sqrt{205}\\Hypotenuse=14.32\\ \approx 14.3 feet $(to the nearest tenth of a foot).\\Therefore, the lenght of the broken part of the tree to the nearest tenth of a foot is 14.3 feet.$