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3 years ago

What is $45 with a markup of 57%

Mathematics

1 answer:

Marrrta [24]3 years ago

5 0

45/100 x 57 + 45 = $70.65

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How long will it take Carlos to walk 8 miles if he is walking 2 mph?

Liula [17]

8/2 = 4

answer: it will take Carlos 4 hours to walk 8 miles

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3 years ago

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Using the graph, predict how many people will be needed to eat 300 pounds of meal?

kkurt [141]

Answer:

100 people

Step-by-step explanation:

if u notice the points are (2,6) and (6,18). 6÷2=3 and 18÷6=3, so if you catch this pattern than you can do 300÷3=100

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3 years ago

Write the resultant of the two vectors as an ordered pair. –6 5 and 6 –5

RideAnS [48]

Answer:

Resultant vector of two vectors is (0, 0).

Step-by-step explanation:

in this question two vectors having ordered pair (-6, 5) and (6, -5) have been given.

We can represent these vectors in the form of

$\vec{A}=-6\hat{x}+5\hat{y}$

and $\vec{A'}=6\hat{x}+(-5)\hat{y}$

Now the resultant of these vectors will be = A + A'

A + A' = $\vec{A}=-6\hat{x}+5\hat{y}$ + $\vec{A'}=6\hat{x}+(-5)\hat{y}$

So the resultant vector = (0 + 0)

Therefore the resultant will be (0, 0)

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3 years ago

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У=-3x+3<br> y = -9x + 15

julia-pushkina [17]

Answer:

(2, - 3 )

Step-by-step explanation:

Given the 2 equations

y = - 3x + 3 → (2)

y = - 9x + 15 → (2)

Substitute y = - 3x + 3 into (2)

- 3x + 3 = - 9x + 15 ( add 9x to both sides )

6x + 3 = 15 ( subtract 3 from both sides )

6x = 12 ( divide both sides by 6 )

x = 2

Substitute x = 2 into either of the 2 equations and solve for y

Substituting into (1)

y = - 3(2) + 3 = - 6 + 3 = - 3

solution is (2, - 3 )

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3 years ago

What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4

Alecsey [184]

Answer: f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: $f(x)=\dfrac{3x^2}{x^2-4}$

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. $x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2$

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at $y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}$

i.e. $y=\dfrac{3}{1}=3$

Hence, f(x) will have horizontal asymptote at y=3.

3 0

3 years ago