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3 years ago

Please help answer ASAP

Mathematics

2 answers:

sweet-ann [11.9K]3 years ago

6 0

0.77875...

which, I'm assuming, they want you to round to the nearest hundredth? So, .78?...

Ksju [112]3 years ago

6 0

First of all, we need to do the expression in parenthesis first.

(4% - 2.25%) = 1.75%

Now, we convert the percent into an integer.

1.75% = 0.0175

Then, we multiply 44.5 by 0.0175

and we get 0.77875.

We have to round the number to the nearest cent.

0.77875 is roughly 0.78

So the answer is $0.78.

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Hans corrio 3 millas en la pista hizo un descanso y luego corio 4/5 de milla mas. Escribe el numero de millas que corrio hans co

givi [52]

Answer:

19/5

Step-by-step explanation:

Aquí, queremos escribir el número total de millas que Hans corrió en forma de una fracción impropia.

Para hacer esto, agregamos todas las millas recorridas.

Matemáticamente, eso sería 3 + 4/5 = 3 4/5 Esta es la forma de fracción mixta.

La fracción impropia es así (5 * 3) + 4/5 = 19/5

8 0

3 years ago

An NBA fan named Mark claims that there are more fouls called on his team 1 point

inn [45]

Answer:

$t=\frac{12.2-11.5}{\frac{1.6}{\sqrt{34}}}=2.551$

$df = n-1=34-1=33$

$p_v =P(t_{(33)}>2.551)=0.008$

Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim

And the best conclusion for this case would be:

b)The p-value is 0.008, indicating sufficient evidence for his claim.

Step-by-step explanation:

Information provided

$\bar X=12.2$ represent the sample mean fould against

$s=1.6$ represent the sample standard deviation

$n=34$ sample size

represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is higher than 11.5 fouls per game:

Null hypothesis: $\mu \leq 11.5$

Alternative hypothesis: $\mu > 11.5$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{12.2-11.5}{\frac{1.6}{\sqrt{34}}}=2.551$

P value

The degreed of freedom are given by:

$df = n-1=34-1=33$

Since is a one side test the p value would be:

$p_v =P(t_{(33)}>2.551)=0.008$

Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim

And the best conclusion for this case would be:

b)The p-value is 0.008, indicating sufficient evidence for his claim.

7 0

3 years ago

Express $3.29 for 24 cans as a unit rate. Round to the nearest cent.

kkurt [141]

Answer:

0.14 cents per can

Step-by-step explanation:

$3.29 divided by 24 cans gives a unit rate or price per can of $0.14 per unit or per can.

Good luck.

Hope this helps!

4 0

3 years ago

Read 2 more answers

In a large data set the 40th percentile is 125 and the 82nd percentile is 158. Approximately what percentage of observations lie

liq [111]

Answer:

42% of observations lie between 125 and 158.

Step-by-step explanation:

Interpretation of a percentile

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

Two values have a percentile, how many are between then?

In this example, y is larger than x.

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

When a value Z is said to be in the yth percentile of a set, y% of the values in the set are lower than V and (100-y)% of the values in the set are higher than V.

Also, (y-x)% of the values are between V and Z.

In this problem, we have that:

125 is the 40th percentile

158 is the 82nd percentile

Approximately what percentage of observations lie between 125 and 158

82 - 40 = 42% of observations lie between 125 and 158.

3 0

3 years ago

A farm increases in value from $800,000 to $1,100,000 over a period of 6 years. Use the formula r=(F/P)^1/n−1 to find the annual

enot [183]

Answer:

Step-by-step explanation:

The formula representing the the annual inflation rate r is expressed as

r = (F/P)1/n−1

Where

n represents the the number of years during which the value increases from P to F

A farm increases in value from $800,000 to $1,100,000 over a period of 6 years. This means that

P = $800,000

F = $1,100,000

n = 6

Therefore,

r = (1100000/800000)1/6−1

r = 1.375/5 = 0.275

6 0

3 years ago