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Ghella [55]
3 years ago
13

A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee ca

n be assigned to an office. In how many ways can the company assign 3 employees to 2 different offices?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Mathematics
1 answer:
vladimir2022 [97]3 years ago
4 0

Answer:

There are 8 ways.

Step-by-step explanation:

For each employee there are two possibilities: first office and second office.

Therefore,

the number of ways the company can assign 3 employees to 2 different offices will be :  

2^{3} = 8

We can also look at this problem like suppose ABC are employees.

We can arrange them like -

0 ABC

ABC 0

AB C

BC A

CA B

A BC

B CA

C AB

So, there are total 8 WAYS.

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Answer:

Correct answer:  x₁ = 1 / √3 = √3 / 3  or  x₂ = - 1 / √3 = - √3 / 3

Step-by-step explanation:

Given:

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this equation is solved by a shift  x² = t and get:

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the solution t₁ = -5 is not accepted because it cannot be x² = -5

we accepted  t₂ = 1 / 3

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God is with you!!!

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