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poizon [28]
2 years ago
12

How do you solve the inequality 6y+3> -18x

Mathematics
1 answer:
Alex17521 [72]2 years ago
6 0
6y + 3 \ \textgreater \  - 18 x

Subtract 3 from both sides:

6 y + 3 - 3 \ \textgreater \  - 18 x - 3

6y \ \textgreater \  - 18 x - 3

Dividade both sides by 6 :

\frac{6y}{6} \ \textgreater \   \frac{-18x-3}{6}

y \ \textgreater \  \frac{-18x-3}{6}

hope this helps!


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kumpel [21]

Answer:

cos ∅ = 80/89

Step-by-step explanation:

As required from the question the picture below represent a triangle UVW . The angle W = 90°. The sides WV = 39 , VU = 89 and UW = 80. The triangle forms a right angle triangle .

Such triangle one can establish trigonometric relationship using the SOHCAHTOA principle.

The question requested us to find the ratio that represent the cosine of  ∠U.

The ∠U is represented as ∅ .

Therefore,

cos ∅ = adjacent/hypotenuse

adjacent = 80. The adjacent side is the non hypotenuse side that is next to the given angle.

hypotenuse = 89 . Hypotenuse is the longest side of a right angle triangle and it opposite the right angle.  

cos ∅ = adjacent/hypotenuse

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Assoli18 [71]
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