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poizon [28]
3 years ago
12

How do you solve the inequality 6y+3> -18x

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0
6y + 3 \ \textgreater \  - 18 x

Subtract 3 from both sides:

6 y + 3 - 3 \ \textgreater \  - 18 x - 3

6y \ \textgreater \  - 18 x - 3

Dividade both sides by 6 :

\frac{6y}{6} \ \textgreater \   \frac{-18x-3}{6}

y \ \textgreater \  \frac{-18x-3}{6}

hope this helps!


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I really need help with Geometry​
Rainbow [258]

Can yu post the problem? my computer won't open the document

4 0
3 years ago
Help!!!!!!!!! i’m confused
Fofino [41]
C is the hypotenuse, which is 10.

a^2 + b^2= c^2
(6)^2 + (8)^2= (10)^2

ANSWER: B) 6^2 + 8^2= 10^2

Hope this helps! :)
5 0
4 years ago
Read 2 more answers
What are the points of trisection of the segment with endpoints (0,0) and (27,27) ?
stiks02 [169]

Given:

Endpoints of a segment are (0,0) and (27,27).

To find:

The points of trisection of the segment.

Solution:

Points of trisection means 2 points between the segment which divide the segment in 3 equal parts.

First point divide the segment in 1:2 and second point divide the segment in 2:1.

Section formula: If a point divides a line segment in m:n, then

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Using section formula, the coordinates of first point are

Point\ 1=\left(\dfrac{1(27)+2(0)}{1+2},\dfrac{1(27)+2(0)}{1+2}\right)

Point\ 1=\left(\dfrac{27}{3},\dfrac{27}{3}\right)

Point\ 1=\left(9,9\right)

Using section formula, the coordinates of first point are

Point\ 2=\left(\dfrac{2(27)+1(0)}{2+1},\dfrac{2(27)+1(0)}{2+1}\right)

Point\ 2=\left(\dfrac{54}{3},\dfrac{54}{3}\right)

Point\ 2=\left(18,18\right)

Therefore, the points of trisection of the segment are (9,9) and (18,18).

6 0
3 years ago
A vertex a is at (-1, -2)
Flura [38]

Answer:

A'(-4,4)

B'(-2,11)

Step-by-step explanation:

6 unit up and 3 unit left

A (-1,-2) : 6 unit up → (-1,4) → 3 unit left → (-4,4)

A'(-4,4)

B (1,5) : 6 unit up → (1,11) → 3 unit left → (-2,11)

B'(-2,11)

8 0
3 years ago
A video game system and several games are sold for $700. The cost of the games is three times as much as cost of the system. Fin
soldier1979 [14.2K]

Answer:

cost of system is $175 and cost of the games is $525

Step-by-step explanation:

Let us take the cost of the system to be X.The games cost 3 times as much as the system and are therefore given 3X. The total cost of the system and the games is $700.Therefore,we form the equation 3X+X=$700.Meaning that 4X=$700 and X is equal to $175.The cost of the system is X therefore it is $175 and the cost of the games is 3X and is therefore $525.

6 0
3 years ago
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