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posledela
3 years ago
9

Give the slope-intercept form of the equation of the line that is perpendicular to –7x – 8y = 12 and contains P(–3, 1)

Mathematics
1 answer:
leva [86]3 years ago
6 0
∵the line is ⊥ to -7x -8y =12
∴its slope = -(-7/-8)= -7/8
∵it passes through P
∴(y-1)=(-7/8)(x+3)
y-1 = (-7/8)x - 21/8
y = (-7/8)x -13/8
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           n  =   \left N } \atop {}} \right.  C_r

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    So  for  a,  where N = 19  and r = 8  

         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

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           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

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                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

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4 years ago
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