Pls help me with this 11-3 and 11-4 u press the link below

1 answer:

7 0

11-3 and 11-4 are both the same problem. Only the names and the numbers
are changed, but the process is exactly the same in both problems.

11-3). If Andy joins the health club, he will pay $34.50 every month.
How many months are in year ? Over here where I come from, we get
12 months each year.
Andy will pay $34.50 twelve times.
All together, he will spend (12) x ($34.50) = $414 on membership.

11-4). Julie rides her bike 5 times a week.
34.75 miles on Monday
34.75 miles on Tuesday
34.75 miles on Friday
34.75 miles on Saturday
34.75 miles on Sunday.
How many 7 total miles does she ride each week ?

(5) times (34.75) = 173.75 miles

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AnnZ [28]

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Solve log 3x -log 13=2. Round to the nearest thousandth if necessary.

Vikentia [17]

$\bf \textit{Logarithm of rationals}\\\\
log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y)
\\\\\\
\textit{Logarithm Cancellation Rules}\\\\
log_a a^x= x\qquad \qquad \boxed{a^{log_ax}=x}\\\\
-------------------------------\\\\
log(3x)-log(13)=2\implies log_{10}(3x)-log_{10}(13)=2
\\\\\\
log_{10}\left( \frac{3x}{13} \right)=2\implies 10^{log_{10}\left( \frac{3x}{13} \right)}=10^2\implies \cfrac{3x}{13}=2
\\\\\\
3x=26\implies x=\cfrac{26}{3}\implies x=8\frac{2}{3}$