Which graph? I can not see any graph in there
Answer:
-4n^4-4n^2-8n+3
Step-by-step explanation:
you combine the like terms
Given that t<span>here
are 20 light bulbs in 5 packages.
The table to find the rate
that gives you the number of light bulbs in 3 packages is given as follows:
![\begin{tabular} {|c|c|c|c|c|c|} Light bulbs&4&8&12&16&20\\[1ex] Packages&1&2&3&4&5 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0ALight%20bulbs%264%268%2612%2616%2620%5C%5C%5B1ex%5D%0APackages%261%262%263%264%265%0A%5Cend%7Btabular%7D)
Three different ways in which the rate can be written are:
12 light bulbs to 3 packages
12 light bulbs : 3 packages
12 light bulbs / 3 packages
</span>
Answer:
When we have a function f(x) = y.
The rate of change between a and b (where a < b) is:
R = (f(b) - f(a))/(b - a)
In this case:
b = 3
a = 1
f(3) = 127
f(1) = 95
R = (127 - 95)/(3 - 1) = 16
The rate of change in that interval is 16.
Answer:
D. 4,704 ft²
Step-by-step explanation:
Giving a scale of 1 in. = 14 ft, to find the actual area of the field represented by the triangular drawing above, convert the length of the base and height to the actual lengths of the field using the scale.
Height of drawing = 8 in.
Actual height = 8*14 = 112 ft
Base of drawing = 6 in.
Actual base = 6*14 = 84 ft
Area of the field = area of ∆
Area = ½*base*height
Area = ½*84*112
Area = 4,704 ft²