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IceJOKER [234]
3 years ago
7

Score: 7.5/50

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Complete Question:

Annette and Rose went to an orchard to pick pears. Annette picked 8\frac{1}{6}

pounds of pears and Rose picked6\frac{1}{8} pounds. How much more did Annette pick than Rose? Write your answer as a reduced mixed number.

Answer:

Annette picked 2\frac{1}{24} pounds of pears more than Rose

Step-by-step explanation:

Pounds of pears picked by Annette = 8\frac{1}{6}

Pounds of pears picked by Rose =  6\frac{1}{8}

To get the difference in the pounds of pears picked by Annette and Rose, we will do a simple subtraction:

Difference in the pounds of pears picked = 8\frac{1}{6} - 6\frac{1}{8}

= 2(\frac{1}{6} - \frac{1}{8})\\= 2\frac{4 - 3}{24} \\= 2\frac{1}{24}

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8 0
3 years ago
En una prueba de natación, Mario hizo el recorrido en ¾ de minuto y David en 4/5 de minuto ¿Cuál es la diferencia entre los dos
slamgirl [31]

Answer:

3 segundos

Step-by-step explanation:

De la pregunta anterior, se nos dice que:

En un evento de natación, Mario hizo el curso en ¾ de minuto

1 minuto = 60 segundos

Por lo tanto = 3/4 de minuto

= 3/4 × 60 segundos

= 45 segundos

David completó el curso en 4/5 de un minuto.

1 minuto = 60 segundos

Por lo tanto = 4/5 de un minuto

= 4/5 × 60 segundos

= 48 segundos

La diferencia entre los dos competidores se calcula como

48 segundos - 45 segundos

= 3 segundos.

Por lo tanto, la diferencia entre los dos competidores = 3 segundos.

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3 years ago
Solve for X : 2 ≥ x3=6<br><br><br> i will give brainliest
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3 years ago
Team A and team B play a series. The first team to win three games wins the series. Each team is equally likely to win each game
andrezito [222]

Answer:

Probability is \frac{1}{4}

Step-by-step explanation:

This problem can be easily done tree diagram.

Few things keep in mind :

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  • Less then or equal to two victories of B.
  • In each matches there are two possibilities either favourable for A or B.

First case if A wins first match

  1.       two victories of B then two of A
  2.       victory of B then A then B then A
  3.       victory of B then A then A

Second case if B wins first match(favorable)

  1.      victory of two B then three A

So total cases are 4 and favorable is one

  probability=\frac{1}{4}

[Tree diagram is in attachment]

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What is the product of (c+8) and (c-5)
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Answer:

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Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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