Answer: The polynomial that describes the projectile's height is:
P(t) = - 16t*2 + 300t
For t = 1 second we have:
P(1) = - 16*1^2 + 300*1
P(1) = 284 ft
The height of the projectile after 1 second is 284 feet.
Step-by-step explanation:
Answer:
4 (5/12). four and five-twelfths
Step-by-step explanation:
1/2 is the same as 2/4, so: 1 1/2 = 1 2/4
1 2/4 + 2 1/4 = 3 3/4
3/4 and 2/3 have a LCM or least common multiple of 12
4 x 3 = 12 and 3 x 4 =12; but whatever you do to the bottom you have to do to the top (3/4) turns into (9/12) and (2/3) turns into (8/12)
9/12 + 8/12 = 17/12 or 1 5/12 as a mixed number
3 + 1 5/12 = 4 5/12
If the Amplitud is 11×2=22cm and the wave was in shm then we can get the wavelength as 11×2=22s.
From the wave equation,
v=fλ Where v⇒speed
f⇒frequency and
λ⇒Wavelength
And we know that;
f=1/T
f = 1/4 =0.25 Hz
∴v = 0.25 ×22 = 5.5 cm/s
Since we know know the speed of the object we can get its time it takes from (0-6.5) cm.
v = fλ = λ/T
∴T = λ/v
= 6.5/5.5
= 1 2/11
= 1.181818s
The time taken for the object <span>to move from x = 0.0 cm to x = 6.5 cm is </span>1.181818s
Answer:
- There are two solutions:
- B = 58.7°, C = 82.3°, c = 6.6 cm
- B = 121.3°, C = 19.7°, c = 2.2 cm
Step-by-step explanation:
You are given a side and its opposite angle (a, A), so the Law of Sines can be used to solve the triangle. The side given is the shorter of the two given sides, so it is likely there are two solutions. (If the given side is the longer of the two, there will always be only one solution.)
The Law of Sines tells you ...
a/sin(A) = b/sin(B) = c/sin(C)
Of course, the sum of angles in a triangle is 180°, so once you find angle B, you can use that fact to find angle C, thus side c.
The solution process finds angle B first:
B = arcsin(b/a·sin(A)) . . . . . . or the supplement of this value
then angle C:
C = 180° -A -B = 141° -B
finally, side c:
c = a·sin(C)/sin(A)
___
A triangle solver application for phone or tablet (or the one on your graphing calculator) can solve the triangle for you, or you can implement the above formulas in a spreadsheet (or even do them by hand). Of course, you need to pay attention to whether the functions involved give or take <em>radians</em> instead of <em>degrees</em>.