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3 years ago

11

Write an equivalent fraction for 1/3+2/5 using 15 as the common denominator

1 answer:

Furkat [3]3 years ago

3 0

An equivalent fraction would be 11/15

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Practice question — Given the trapezoid to the right find the length of legs in the following isosceles trapezoid

ad-work [718]

Given:

A figure of an isosceles trapezoid with bases 18 and 24, and the vertical height is 4.

To find:

The legs of the isosceles trapezoid.

Solution:

Draw another perpendicular and name the vertices as shown in the below figure.

From the figure it is clear that the AEFD is a rectangle. So,

$EF=AD=18$

Since ABCD is an isosceles trapezoid, therefore in triangle ABE and DCF,

$AB=DC$ (Legs of isosceles trapezoid)

$AE=DF$ (Vertical height of isosceles trapezoid)

$m\angle AEB=m\angle DFC$ (Right angle)

$\Delta ABE\cong \Delta DCF$ (HL postulate)

$BE=CF$ (CPCTC)

Now,

$BE+EF+FC=BC$

$2BE+18=24$

$2BE=24-18$

$2BE=6$

$BE=3$

Using Pythagoras theorem in triangle ABE, we get

$Hypotenuse^2=Perpendicular^2+Base^2$

$(AB)^2=(AE)^2+(BE)^2$

$(AB)^2=(4)^2+(3)^2$

$(AB)^2=16+9$

$(AB)^2=25$

Taking square root on both sides, we get

$AB=\pm \sqrt{25}$

$AB=\pm 5$

Side length cannot be negative. So, $AB=5$ .

Therefore, the length of legs in the given isosceles trapezoid is 5 units.

3 0

3 years ago

A football player completes 19 of his 25 passes during the season. What percent of his passes did the player complete? Use fract

d1i1m1o1n [39]

19/25 is the answer for this one.

5 0

3 years ago

A process produces a certain part with a mean diameter of 2 inches and a standard deviation of 0.05 inches. The lower and upper

Nimfa-mama [501]

Answer:

The value of Cp (measure of potential capability) is 6.33.

Step-by-step explanation:

Given information: Process average = 2 inches, process standard deviation = 0.05 inches, lower engineering specification limit = 1.6 inches and upper engineering specification limit =3.5 inches.

The formula for Cp (measure of potential capability) is

$CP=\frac{USL-LSL}{6\sigma}$

Where, USL is upper specification limit, LSL is specification limit, σ is process standard deviation.

Substitute USL=3.5, LSL=1.6 and σ=0.05 in the above formula.

$CP=\frac{3.5-1.6}{6(0.05)}$

$CP=\frac{1.9}{0.3}$

$CP=6.3333$

$CP\approx 6.33$

Therefore the value of Cp (measure of potential capability) is 6.33.

7 0

3 years ago

16. PHYSICS The formula h = 1201 - 16t2 gives the height h in feet of an object 1 seconds after it is shot upward from

Murrr4er [49]

<h3><u>Question:</u></h3>

The formula h = 120t-16t^2 gives the height h in feet of an object t seconds after it is shot upward from Earth's surface with an initial velocity of 120 feet per second. What will the height of the object be after 6 seconds?

<h3><u>Answer:</u></h3>

The height of object after 6 seconds is 144 feet

<h3><u>Solution:</u></h3>

<em><u>The formula that gives the height of an object is:</u></em>

$h = 120t - 16t^2$

Where,

h is the height in feet and t is the time in seconds

To find: height of the object be after 6 seconds

To find the height of the object be after 6 seconds, substitute t = 6

$h = 120 \times 6 -16(6)^2\\\\h = 720 - 16 \times 36\\\\h = 720 - 576\\\\h = 144$

Thus height of object after 6 seconds is 144 feet

3 0

3 years ago

50 points! help, quick please!

kondor19780726 [428]

Answer:

Step-by-step explanation:

The two rules are :-

15 - 10(n - 1)

25 - 10n

6 0

3 years ago

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