Answer:
a) P=0.2503
b) P=0.2759
c) P=0.3874
d) P=0.2051
Step-by-step explanation:
We have this information:
25% of American households have only dogs (one or more dogs)
15% of American households have only cats (one or more cats)
10% of American households have dogs and cats (one or more of each)
50% of American households do not have any dogs or cats.
The sample is n=10
a) Probability that exactly 3 have only dogs (p=0.25)

b) Probability that exactly 2 has only cats (p=0.15)

c) Probability that exactly 1 has cats and dogs (p=0.1)

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

There is no solution. Here is the explanation with both of the methods :)
Answer:
2.5
Step-by-step explanation:
(I'm assuming you're doing this the same way I learned it, if not I'm sorry if it doesn't make sense)
=
Cross multiply
12x=30
Divide
x=2.5
This is just one way to do the problem. An easier way is to simplify the fractions.
=
You can either cross multiply or figure out that 2 is half of four and simply divide 5 by 2 which will also result in 2.5
37 1/2. Since the decimal is in the tens place, the best, and easiest, denominator to use is 10, which results in 37 5/10 which then can be simplified into 37 1/2