Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.
Hope I could help.
Answer:
E) b^2
Step-by-step explanation:
Solving the first equation for a, we get ...
a - b = 0
a = b . . . . . . add b to both sides
Now, the expression ab can be rewritten as
ab = bb = b^2 . . . . . . substitute b for a
Answer:
option a
Step-by-step explanation:
markme brainliest
A is aldult tickets
b is child tickets
b = 2/3 a
7a + 12b = 90
7a + 12 x 2/3 a = 90
7a + 8a = 90
15a = 90
a = 6; b = 4
Answer:
Step-by-step explanation:
23x-12-4x+5x
24x-12 combine the 23x-4x+5x to get 24x
19-14+3x+12x
15x+5 19-14=5 3x+12x=15x
6x+19-14x+9
-8x+28 -14x+6x= -8x 19+9=28
