sum of two angles of triangle are equal to the exterior angle of triangle
AD = DB
Angle ADE = Angle CDB
Angle DAE = Angle DBC (Alternate angles)
Angle DEA = Angle DCB (Alternate angles)
Since you have two congruent angles and one congruent side, triangle ADE is congruent to triangle CDB. This means that DE is congruent to DC implying D is the midpoint of CE.
Lines are perpendicular if the slope of one is the negative reciprocal of the other. In this case the slopes are -8/3 and 8/3, so while negative they are not reciprocal. So no, the two lines intersect but are not perpendicular.
Answer:
4 units
Step-by-step explanation:
Let ABC be isosceles right angled ∆ right angled at B
By Pythagoras theorem,
AC² = AB² + BC²
(√32)² = 4² + s²
32 = 16 + s²
s² = 32 - 16
s² = 16
s = √16
s = 4 units.
Therefore s = 4 units
Hope it helps...
I think it would be 10.5, although I'm not sure I hope this helps
