Diagonal cross-section of a sphere produces which two dimensional shape

1 answer:

7 0

Every cross-section of a sphere will be a circle.

Answer: circle

Any further questions about this? Or how I got my answer?

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Rank and alice are penguins. at birth, frank's beak was 1.95 inches long, while alice's was 1.50 inches long. homework help ✎ fr

miskamm [114]

<span>F for Frank, A or Alice. F(initial)=1.95 inches A(initial)=1.50 inches Frank's equation at .25 inches per year and t representing year variable. F=1.95+.25t Alice's equation at .40 inches per year and t representing year variable. A=1.5+.40t To figure out how old they will be when their beaks are the same lengths set the equations equal to eachother as the equations are length. 1.95+.25t=1.5+.40t .45=.15t t=3 years</span>

5 0

3 years ago

4x + 5y = 10

Vika [28.1K]

Answer:

For A = 32/5 and B = 8 the system of equations will have infinitely many solutions.

Step-by-step explanation:

Given equations are:

4x + 5y = 10

Ax + By = 16

The general form of linear equation in two variables is given by:

$ax+by = c$

Here a, b and c are constants and x,y are variables.

In the given equations, after comparing with the general form

$a_1 = 4\\b_1 = 5 \\c_1 = 10\\a_2 = A\\b_2 =B\\c_2 = 16$

"In order for a system of equations to have infinity many solutions,

$\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$ "

Putting the values we get

$\frac{4}{A} = \frac{5}{B} = \frac{10}{16}\\\frac{4}{A} = \frac{5}{B} = \frac{5}{8}\\Now\\\frac{4}{A} = \frac{5}{8}\\\frac{A}{4} = \frac{8}{5}\\A = \frac{8}{5} * 4\\A = \frac{32}{5}\\And\\\frac{5}{B} = \frac{5}{8}\\\frac{B}{5} = \frac{8}{5}\\B = 8$

Hence,

For A = 32/5 and B = 8 the system of equations will have infinitely many solutions.

5 0

3 years ago

Hey can you please help me posted picture of question

jenyasd209 [6]

The equation of parabola is $x=ay^2$ . If a is positive and $y^2$ is always greater than zero or equal to zero, then x is also greater or equal to zero. This means that parabola is determined for non-negative x and for all real y.

Tha canonical equation of parabola is $y^2=2px$ , where p>0. The branches of this parabola go up in positive y-direction. When you change x to y and y to x, then the branches of parabola go in positive x-direction, that is right.