Answer with Step-by-step explanation:
We are given that function f(x) which is quadratic function.
x -intercept of function f(x) at (-1,0) and (-3,0)
x-Intercept of f means zeroes of f
x=-1 and x=-3
Range of f =[-4,
)
g(x)=
Therefore, x-intercept of g(x) at (-1,0) and (-3,0).
Substitute x=-2
By comparing with the equation of parabola
Where vertex=(h,k)
We get vertex of g(x)=(-2,-2)
Range of g(x)=[-2,)
Zeroes of f and g are same .
But range of f and g are different.
Range of f contains -3 and -4 but range of g does not contain -3 and -4.
f and g are both quadratic functions.
Answer:
Yes, an arrow can be drawn from 10.3 so the relation is a function.
Step-by-step explanation:
Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.
The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.
In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.
However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.
Answer:
A
Step-by-step explanation:
(4+5)7=9*7=63
You can write the equation
x+1+x+3+x+5=576
Combine like terms
3x+9=576
Subtract 9 from both sides
3x+9-9=576-9
3x=567
Divide both sides by 3
3x/3=567/3
x=189
The first integer is 190, the second is 192 and the third is 194 (enter it into the original equation to get those answers)
