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4 years ago

What is the volume and surface area of these right rectangular prisms

Mathematics

1 answer:

worty [1.4K]4 years ago

5 0

#1 surface area= 26

volume=24 (I think)

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There’s a image what’s the answer?

irina [24]

Answer:

B. 59°

Step-by-step explanation:

<AOC=77°

<BOC=?

THEREFORE,

<AOC=<BOC+<AOB

77° =7x+17+3x

77°-17=7x+3x

60=10x

x=60/10

x=6°

Now,

<BOC=7x+17

=7*6+17

=42+17

=59

7 0

2 years ago

The sum of two numbers is 24. the diffrence is 10. what are the numbers

topjm [15]

Answer:

The two numbers are 17 and 7.

Step-by-step explanation:

x+y=24

x-y=10

------------

2x=34

x=34/2

x=17

17-y=10

y=17-10

y=7

6 0

3 years ago

How do I write three different fractions that simplify to 1/4

My name is Ann [436]

2/8
4/12
6/24

they can all be simplified to 1/4

8 0

3 years ago

Verify which of the following are identities.

ch4aika [34]

Answer:

Step-by-step explanation:

Equation 1:

$1+\frac{\cos^{2} \theta}{\cot^{2} \theta(1-\sin^{2} \theta)}\\ \\ 1+\frac{\sin^{2} \theta}{\cos^{2} \theta} \\ \\ 1+\tan^{2} \theta \\ \\ \sec^{2} \theta$

Equation 2:

$15\cos \theta \left(\frac{1}{\cos \theta}-\frac{\cot \theta}{\csc \theta} \right) \\ \\ 15\cos \theta \left(\frac{1}{\cos \theta}-\frac{\cos \theta / \sin \theta}{1/\sin \theta} \right) \\ \\ 15\cos \theta \left(\frac{1}{\cos \theta}-\cos \theta \right) \\ \\ 15\cos \theta \left(\frac{1-\cos^{2} \theta}{\cos \theta} \right) \\ \\ 15(1-\cos^{2} \theta) \\ \\ 15\sin^{2} \theta$

6 0

2 years ago

The mean height of women in a country (ages 20minus29) is 64.2 inches. A random sample of 75 women in this age group is select

padilas [110]

Answer:

$z=\frac{65-64.2}{\frac{2.84}{\sqrt{75}}} = 2.440$

And we can find the probability using the complement rule and with the normal standard table like this:

$P(Z>2.440) =1-P(Z$

The probability that the mean height for the sample is greater than 65 inches is 0.007

Step-by-step explanation:

Let X the random variable that represent the women heights of a population, and we know the following parameters

$\mu=64.2$ and $\sigma=2.84$

We are interested on this probability

$P(X>65)$

Since the sample size selected is 75>30 we can use the centrel limit theorem and the appropiate formula to use would be the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we find the z score for 65 inches we got:

$z=\frac{65-64.2}{\frac{2.84}{\sqrt{75}}} = 2.440$

And we can find the probability using the complement rule and with the normal standard table like this:

$P(Z>2.440) =1-P(Z$

The probability that the mean height for the sample is greater than 65 inches is 0.007

7 0

3 years ago