Subtract 6 from 50:
50-6 = 44
Divide 44 by 2:
44/2 = 22
add 6:
22+6 = 28
There is 22 in the smaller class and 28 in the larger class.
9 + 10=21 :)
9=3 x3
10= 2 x 5
3x5=15
3x2=6
15 + 6 = 21 :)
Answer:
It's like solving a quadratic, but in reverse, and in this case you'll arrive at x2+x−12=0
Explanation:
We're going to go "backwards" with this problem - normally we're asked to take a quadratic equation and find the roots. So we'll do what we normally do, but in reverse:
Let's start with the roots:
x=3, x=−4
So let's move the constants over with the x terms to have equations equal to 0:
x−3=0, x+4=0
Now we can set up the equation, as:
(x−3)(x+4)=0
We can now distribute out the 2 quantities:
x2+x−12=0
Answer:
Step-by-step explanation:
Given: f(x) = 4(3x - 5)
Is required to find f⁻¹(x)
f(x) = y = 4(3x - 5)
∴ y = 4 * 3x - 4 * 5
∴ y = 12x - 20 ⇒ add 20 to both sides
∴ y + 20 = 12x ⇒ divide both sides by 12
∴ 
Replace the places of x and y.
∴ 
∴
