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Mkey [24]
3 years ago
9

Please help solve 5!3!/6! = ?

Mathematics
2 answers:
Marina86 [1]3 years ago
8 0
The exclamation points mean you're looking for factorials.
5!3!/6! = ((5*4*3*2*1)(3*2*1))/(6*5*4*3*2*1)
(120*6)/720
720/720 = 1
dangina [55]3 years ago
6 0
5! = 5 * 4 * 3 * 2 * 1 = 120
3! = 3 * 2 * 1 = 6
6! = 6 * 5 * 4 * 3 * 2 * 1 = 720

120 * 6 / 720

= 1
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Yesterday, Fairlane got 1 1/2 inches of rain. It got 3/4 of that rain before 3:00 P.M. How much rain did Fairlane get before 3:0
aalyn [17]

Answer:

3/4

Step-by-step explanation:

1 1/2

3/2 make this 6/4 so you can have a common denominator

3/4

Then you subtract and boom 3/4 it also says in the problem lol

3 0
3 years ago
Find each f(c) using synthetic substitution. f(x) = –x7 + 4x6 – 4x5 – 6x4 – 3x3 – 6x2 – x – 2; c = –5
zmey [24]

Answer:

<em>f(-5)=149603</em>

Step-by-step explanation:

<u>Synthetic Substitution</u>

It's a method to find the value of a polynomial for a given value of x. The polynomial we want to evaluate is

f(x) = -x^7 + 4x^6 - 4x^5 - 6x^4 - 3x^3 - 6x^2 - x - 2

at x=-5

We can, of course, just replace x for -5 and compute the powers, products and sums and subtractions, but we can use the synthetic substitution to avoid the powers, just by multiplying and adding or subtracting. The method requires us to use only the coefficients of the ordered and complete polynomial as shown:

-1  4  -4  -6  -3  -6  -1  -2

Now we set up an arrangement where we can place some operations

     -1  4  -4  -6  -3  -6  -1  -2

-5

The second row and a new third row will be filled by computing values as explained below.

The first value of the third row is the very same first coefficient (-1)

     -1   4   -4   -6   -3   -6   -1   -2

-5

     -1

The second value of the second row is the -5 times the first value of the third row: (-5)(-1)=5

Next value of the third row is the sum of the values above of it: 4+5=9

-1 4 -4 -6 -3 -6 -1 -2

-5  5

-1 9

Now we proceed the same with next values to get the full arrangement or synthetic substitution

-1 4 -4 -6 -3    -6  -1  -2

-5  5 -45 245 -1195 5990 -29920 149605

-1 9 -49 239 -1198 5984 -29921 149603

The very last value of the third row is the required substitution

f(-5)=149603

The formatted table can be seen in the image below

5 0
4 years ago
the length of a rectangle is 9 inches more than three times the width. the perimeter is 98 inches. find the length and width
Mars2501 [29]
Here is the equation:

Your goal is to get a number variable

2w+2(3w+9)=98

Solve the parentheses first, namely "w" by itself on one side

2w+6w+18=98

Add common  values

8w+18=98

Minus 18 from both sides

8w+18-18=98-18

It is now

8w=80

Now, divide 80 by 8

80÷8=10

w=10

Lets check:

2(10)+ 2(30+9)=98

20+60+18=98

Which is correct

So that means each side of the width is 10 inches
and each length side is 39 inches

Answer: So that means that width side is 10 inches each and each length side is 39 inches each. 10+10+39+39=98 inches

 
8 0
4 years ago
25 (a square) - 4 (b square) + 28bc - 49 (c square)
LUCKY_DIMON [66]

Answer:

(5a - [2b - 7c]) and (5a + [2b + 7c])

Step-by-step explanation:

Factor 25a^2 - 4b^2 + 28bc - 49c^2.

Note that - 4b^2 + 28bc - 49c^2 involves the variables b and c, whereas 25a^2 has only one variable.  Thus, try to rewrite - 4b^2 + 28bc - 49c^2 as the square of a binomial:

- 4b^2 + 28bc - 49c^2 = -(4b^2 - 28bc + 49c^2), or

                                        -(2b - 7c)^2.

Thus, the original  25a^2 - 4b^2 + 28bc - 49c^2  looks like:

                               [5a]^2 - [2b - 7c]^2

Recall that a^2 - b^2 is a special product, the product of (a + b) and (a - b).  Applying this pattern to the problem at hand, we conclude:

Thus,   [5a]^2 - [2b - 7c]^2 has the factors (5a - [2b - 7c]) and (5a + [2b + 7c])

8 0
3 years ago
Consider the system of equations.
Xelga [282]

Answer:

D and C

Step-by-step explanation:

Given the 2 equations

3x - y = 5 → (1)

2x + 3y = - 15 → (2)

Multiplying (1) by 3 and adding to (2) will eliminate the y- term

9x - 3y = 15 → (3)

Add (2) and (3) term by term to eliminate y

11x + 0 = 0

11x = 0 ⇒ x = 0

Substitute x = 0 into either of the 2 equations and solve for y

Substituting into (2)

2(0) + 3y = - 15

0 + 3y = - 15

3y = - 15 ( divide both sides by 3 )

y = - 5

solution is (0, - 5 )

3 0
3 years ago
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