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Anastasy [175]
2 years ago
11

Simplify. (ep)3 3ep e3p3 e3p ep3

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
7 0
B
3 goes to both e and p
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Which term describes the point where three medians of a triangle intersect
Hitman42 [59]
The correct answer is centriod
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3 years ago
Read 2 more answers
Fatima paid for 5 pallets of grass to be delivered.
slava [35]
Fatima paid for 5 pallets of grass to be delivered.
• Each pallet of grass cost $129.95.
• Fatima paid $76.20 for delivery.
What is the total amount Fatima paid?
A $725.95
B $649.75
C $581.95
D $1,030.75
Answer:
A $725.95
Step-by-step explanation:
Given:
Number of Pallets = 5
Cost of each pallet = $129.95
Total amount spend on Pallets = Number of Pallets × Cost of each pallet =
Also given;
Amount spend on Delivery = $76.20
Total Amount Paid by Fatima = Total amount spend on Pallets + Amount spend on Delivery =
Hence Fatima paid a total amount of $725.95.
5 0
3 years ago
Determine the value of each unknown variable
Oksi-84 [34.3K]
X=18 and y=10 because they are both 90degree angles therefore all you have to do is solve the equations: 5x=90 and 9y=90.
4 0
3 years ago
Three angles of quadrilateral ABCD have measures 66, 95 and 114. what is the value of x?
vampirchik [111]
To find the value of x, assuming it is the value of the missing angle in the quadrilateral, you need to know that the sum of the angles in any quadrilateral equals 360.

360 - (66 + 95 + 114) = 85 degrees.

x = 85 degrees
8 0
2 years ago
Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl
amm1812

Answer:

1. P(s_1|I)=\frac{1}{11}

2. P(s_2|I)=\frac{8}{11}

3. P(s_3|I)=\frac{2}{11}

Step-by-step explanation:

Given information:

P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3

P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1

(1)

We need to find the value of P(s₁|I).

P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}

P(s_1|I)=\frac{0.015}{0.165}

P(s_1|I)=\frac{1}{11}

Therefore the value of P(s₁|I) is \frac{1}{11}.

(2)

We need to find the value of P(s₂|I).

P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}

P(s_2|I)=\frac{0.12}{0.165}

P(s_2|I)=\frac{8}{11}

Therefore the value of P(s₂|I) is \frac{8}{11}.

(3)

We need to find the value of P(s₃|I).

P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}

P(s_3|I)=\frac{0.03}{0.165}

P(s_3|I)=\frac{2}{11}

Therefore the value of P(s₃|I) is \frac{2}{11}.

4 0
3 years ago
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