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Debora [2.8K]
3 years ago
14

Find limit as x approaches 4 from the left of the quotient of the absolute value of the quantity x minus 4, and the quantity x m

inus 4 . You must show your work or explain your work in words.
See below for the mathematical form of the equation.

Mathematics
2 answers:
babunello [35]3 years ago
8 0
This is fun

one way is to aproximate by getting values closer and closer to the value
the small negative sign on the top left of the 4 means we need to aproximate from the left, or from values less than 4 to 4

so like using 3.9, 3.99. 3.999, etc

if we did 3.9, we get 0.1/-0.1=-1
if we did 3.99, we get 0.01/-0.01=-1
if we did 3.999, we get 0.001/-0.001=-1
I notice a pattern

so therefor I say the limit as x approaches 4 from the left is -1
Degger [83]3 years ago
5 0

Answer:

-1

Step-by-step explanation:

Given,

lim_{x\rightarrow 4^{-}} \frac{|x-4|}{x-4}

Let h represents a small change,

So, we can write,

lim_{x\rightarrow 4-h} \frac{|x-4|}{x-4}

=\frac{|4-h-4|}{4-h-4}

=\frac{|-h|}{-h}

=\frac{h}{-h}

=-1

Hence, the value of the given limit is -1.

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• Notice that you can divide the rectangle into two squares with equal area. How can you estimate the side length of each​ square?

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3 years ago
2 is multiplied by the difference of a number and 4
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(x - 4) * 2

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Question 2 (2 points)
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Answer:

4) The limit does not exist.

General Formulas and Concepts:

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Step-by-step explanation:

*Note:

For a limit to exist, the right-side and left-side limits must be equal to each other.

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x ,\ x < 5\\8 ,\ x = 5\\x + 3 ,\ x > 5\end{array}

<u>Step 2: Find Left-Side Limit</u>

  1. Substitute in function [Left-Side Limit]:                                                       \displaystyle \lim_{x \to 5^-} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                          \displaystyle \lim_{x \to 5^-} 5 - x = 5- 5 = 0

<u>Step 2: Find Left-Side Limit</u>

  1. Substitute in function [Right-Side Limit]:                                                     \displaystyle \lim_{x \to 5^+} x + 3
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8

∴ since  \displaystyle \lim_{x \to c^+} f(x) \neq \lim_{x \to c^-} f(x)  ,  \displaystyle  \lim_{x \to 5} f(x) = \text{DNE}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0
3 years ago
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